Consider the intersection curve C in the first octant, between the surfaces S1: z = 1 - x2 and S2: y = 2x. Let P = (1/2 , 1, 3/4) a point on C, as shown in the figure. the figure is in the first attached image A vector tangent to the curve C at P corresponds to:

Advanced Engineering Mathematics
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ISBN:9780470458365
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Chapter2: Second-order Linear Odes
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Consider the intersection curve C in the first octant, between the surfaces S1: z = 1 - x2 and S2: y = 2x. Let P = (1/2 , 1, 3/4) a point on C, as shown in the figure.

the figure is in the first attached image

A vector tangent to the curve C at P corresponds to:

the answers are in the second image

A) 7 = (1,1, –2)
%3D
B) 7 = (1,2, –2)
C) 7 = (1, 1, –1)
D) 7 = (1,2, –1)
Transcribed Image Text:A) 7 = (1,1, –2) %3D B) 7 = (1,2, –2) C) 7 = (1, 1, –1) D) 7 = (1,2, –1)
z =1-2
y = 2x
Transcribed Image Text:z =1-2 y = 2x
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