Consider the indefinite integral a= The integrand decomposes into the form ax + b + where b= C= d = с + x − 1 (4x³ + 3x² + 1x − 6 x² - 1 14.0³. d x + 1 x² - 1 Enter an integer or decimal number [more..] Integrating term by term, we obtain that (4x³ + 3x² + 1x 6 S42³ + dx dx. +C.

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