Consider the inconsistent system HO-A 0 (i) Find the least squares solution to this system. (ii) Find the least squares error to your solution.

The nonlinear system has six real solutions. 4x0 x₁ + x₂ = X0X3 xo - 2x₁ + 3x₂ = x₂x3 -xo + 3x₁ - 2x₂ = X₁ X3 x² + x² + x² = 1 (a) Show that if (x0, X₁, X2, X3)T is a solution, then (-X0, −X₁, −X₂, X3)¹ is also a solution.

Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, set x3 = t and solve for X₁ and X2.) X1 - 3x3 = -5 3x1 + x₂ - 2x3 = 1 2x1 + 2x2 + x3 = 1 (X1, X2, X3) = Need Help? Read It ►

Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination