Consider the function x²+2x-1 if x ≤ -1 f(x) = 3/8x if 1< x < 1 2x+4 if x 1 3 -1, we compute (a) To determine whether f is differentiable at x=-1 lim h→0+ 2/3 f(−1 + h) − f(−1) h - = lim h→0+ lim h→0- 0 ƒ(−1 + h) − f(−1) h = lim h→0- (b) To determine whether f is differentiable at x = 0), we compute lim h→0 f(h) — f(0) h lim 0+4 (c) To determine whether f is differentiable at x = 1, we compute lim h→0+ lim h→0- ƒ(1+ h) − f(1) h f(1+h) − f(1) h - = lim 2h/3/h h→0+ = lim h→0- (d) Classify the differentiability of f at each of the points. f is differentiable at x=a 1. x = 1 f has a vertical tangent line at x=a 2. x = 0 f has a cusp at x=a 3. x=-1 = 2/3 = 2/3

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Chapter9: Quadratic Equations And Functions
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Consider the function
x²+2x-1 if x-1
f(x)=√√8x
2x+4
3
if 1<<1
if x 1
(a) To determine whether of is differentiable at x = -1, we compute
lim
h→0+
2/3
ƒ(−1 + h) − f(−1)
h
=
lim
h→0+
lim
h→0-
0
f(-1+h) − f(-1)
h
=
lim
h→0-
(b) To determine whether f is differentiable at x =
lim
h→0
f(h) - f(0)
h
lim
h→0
(c) To determine whether f is differentiable at x =
lim
h→0+
f(1+ h) − f(1)
h
f(1+h) − f(1)
-
= lim 2h/3/h
h→0+
lim
h→0-
h
lim
h→0-
(), we compute
1, we compute
(d) Classify the differentiability of f at each of the points.
f is differentiable at x=a
1. x=1
f has a vertical tangent line at x=a 2. x = 0
f has a cusp at x=a
3. x = -1
=
2/3
= 2/3
Transcribed Image Text:Consider the function x²+2x-1 if x-1 f(x)=√√8x 2x+4 3 if 1<<1 if x 1 (a) To determine whether of is differentiable at x = -1, we compute lim h→0+ 2/3 ƒ(−1 + h) − f(−1) h = lim h→0+ lim h→0- 0 f(-1+h) − f(-1) h = lim h→0- (b) To determine whether f is differentiable at x = lim h→0 f(h) - f(0) h lim h→0 (c) To determine whether f is differentiable at x = lim h→0+ f(1+ h) − f(1) h f(1+h) − f(1) - = lim 2h/3/h h→0+ lim h→0- h lim h→0- (), we compute 1, we compute (d) Classify the differentiability of f at each of the points. f is differentiable at x=a 1. x=1 f has a vertical tangent line at x=a 2. x = 0 f has a cusp at x=a 3. x = -1 = 2/3 = 2/3
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