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Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len (b)-1)] return foo(a-1, [1] + b_new + [1])

Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len (b)-1)] return foo(a-1, [1] + b_new + [1])

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Python

Big-O Coding

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Big-O Coding Exercise: Given: Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) Question: The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T ) +0 Notes when answering: Note that when complexities or expressions are asked: • Answer without the big-O. Assume a, x, and y are very large. Use 'log()' to add the logarithmic function (e.g. n log(n) is written as n* log(n )). Use "(e)' to create exponents (e.g. 2" is written as 2^(n )). • Use 'sqrt()' to create square roots (e.g. Vn is written as sqrt(n )). • Remember that log, log a/ log b. a =
Transcribed Image Text:Big-O Coding Exercise: Given: Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) Question: The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T ) +0 Notes when answering: Note that when complexities or expressions are asked: • Answer without the big-O. Assume a, x, and y are very large. Use 'log()' to add the logarithmic function (e.g. n log(n) is written as n* log(n )). Use "(e)' to create exponents (e.g. 2" is written as 2^(n )). • Use 'sqrt()' to create square roots (e.g. Vn is written as sqrt(n )). • Remember that log, log a/ log b. a =
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