Consider the function below: 17 6 y = (x+3)(x+1)(x – 2) 4 3 5 12 1 -7 -6 -5 -4 -3 -2 -1 12 3 4 5 6 7 -1 2 -3 |-4 -5

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section: Chapter Questions
Problem 63RE
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Graph in the image: Over the intervals of (−∞,−3)∪(−1,2) the graph is considered to be increasing, decreasing, positive or negative?
Consider the function below:
17
y = (x+3)(x+1)(x – 2)
4
15
3
12
1
-7 -6 -5 -4 -3 -2 -1
1 2 3 4 5 67
|-1
-2
-3
|-4
-5
16
Transcribed Image Text:Consider the function below: 17 y = (x+3)(x+1)(x – 2) 4 15 3 12 1 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 67 |-1 -2 -3 |-4 -5 16
Expert Solution
Step 1
  • when the graph is below the x-axis in an interval the graph is negative in that interval.
  • when the graph is above the x-axis in an interval the graph is positive in that interval.
  • when the slope of the graph is positive in an interval the graph is increasing in that interval.
  • when the slope of the graph is negative in an interval the graph is decreasing in that interval.
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