Consider the following variation on MergeSort: instead of dividing a list (say, of integers) evenly (that is, half and half or half and half plus 1) at all levels of recursion, we choose to divide a list this way - a left list that consists of exactly one integer and a right list that consists of the remaining integers. The time-complexity of this variation of MergeSort is: (a) O(n log n) (b) O(n²) (c) O(n) (d) none of the above
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