Consider the following statements: (3) stackType stack (50); int num; Suppose that the input is: 31 47 86 39 62 71 15 63 Show what is output by the following segment of code: cin >> num; while (cin) { if (!stack.isFullStack()) { if (num 2 == 0 || num & 3 == 0) stack.push (num); else if (!stack.isEmptyStack()) { cout << stack.top() << " "; stack.pop(); } else stack.push (num + 3); 62 33 Stack Elements: 15 60 56 34 35 60 Stack Elements: 23 45 67 78 34 62 Stack Elements: 63 15 39 86 None of the above cin >> num; } cout << endl; cout << "Stack Elements: "; while (!stack.isEmptyStack()) ( cout << " " << stack.top(); stack.pop(); } cout << endl;

Project Overview: This project is for testing the use and understanding of stacks. In this assignment, you will be writing a program that reads in a stream of text and tests for mismatched delimiters. First, you will create a stack class that stores, in each node, a character (char), a line number (int) and a character count (int). This can either be based on a dynamic stack or a static stack from the book, modified according to these requirements. I suggest using a stack of structs that have the char, line number and character count as members, but you can do this separately if you wish.Second, your program should start reading in lines of text from the user. This reading in of lines of text (using getline) should only end when it receives the line “DONE”.While the text is being read, you will use this stack to test for matching “blocks”. That is, the text coming in will have the delimiters to bracket information into blocks, the braces {}, parentheses (), and brackets [ ]. A string…

Please elaborate on the distinction between the bound and unbounded stack.

solution for subpart 4

Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; Node<int> *aNode; while(curNode->getItem()<7){        aNode=curNode;        curNode=curNode->getNext(); } a=aNode->getItem();   A. 5 B.8 C.0 D.7

Suppose that you want to create the following program:   void copyStack(std::stack<int> &srcStack, std::stack<int> &dstStack);   This operation copies the elements of srcStack in the same order onto dstStack. Consider the following statements: Int main() { Std::stack<int> stack1; Std::stack<int> stack2;   … copyStack(stack1, stack2);   The function copyStack(stack1, stack2); copies the elements of stack1 onto stack2 in the same order. That is, the top element of stack1 is the top element of stack2, and so on. The old contents of stack2 are destroyed and stack1 is unchanged. Note that std::stack<int> is a C++ standard library stack object type.   Complete the following program     void copyStack(std::stack<int> &srcStack, std::stack<int> &dstStack) {    //  check if srcStack is empty -> error message is printed and return         // remove all the elements of dstStack         // create a temporary stack tempStack for…

#include<bits/stdc++.h>using namespace std;#define MAX 1000 //Maximum size of stack class Stack{   int top;// to store top of stack   public:   int elements[MAX]; //Integer array to store elements   Stack(){ //class constructor for initialization        top=-1;   }    bool push(int x) {         if(top>=(MAX-1)) //Condition for top when stack because full         {              cout<<"Stack is full\n";               return false;          }         else          {           ++top; //Increasing top value            elements[top]=x; //storing it to element in to stack            return true;            }}int pop(){     if(top<0)// Condition for top when stack is empty     {      cout<<"stack is empty\n";      return INT_MIN;      }      else      {         int x=elements[top--];//poping out the element for stack by decreasing to element         return x;       }}int  display(){if(top<0)//Condition for top when stack is empty   {      cout<<"Stack is…

0:00 I ZVV 58 Stack s - new Stack(); s. push(10); s. push(20); s. push(30); s. push(40); // stack created with elements- 10 20 30 40 59 60 61 62 63 64 65 sum(s); 66 public static void sum(stack s){ Integer sum = 0; stack tmp = new Stack(); // move the stack to new stack, it will be in reverse orde // simultaneously sum the elements while (Is.isEmpty())( tmp.push(s.pop(); sum t tmp.peek(); 67 68 69 70 71 72 73 74 sum t= tmp.peek (); 74 75 // move to original stack while (Itmp.isEmpty()){ s.push(tmp.pop()); system.out.println("sum= "+sum.tostring()); OUTPUT- 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack 40 pushed into stack 30 pushed into stack 20 pushed into stack 10 pushed into stack 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack Sum= 100 Sum of 10, 2O, 30, 40 = 100 I hope it helps. For any doubt, feel free to ask in comments, and give upvote if u get the answer.