Consider the following reaction at constant pressure. Use the information here to determine the value of AS surr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N₂(g) +202(g) → 2NO₂(g) AHrxn = +88.4 kJ mol-1 ASsurr = +88.4J K-1 mol-1¹, reaction is spontaneous ⒸASsurr = -88.4J K-1 mol-1, reaction is spontaneous Assurr = -88.4J K-1 mol-1, reaction is not spontaneous ⒸASsurr = +297 J K-1 mol-1, reaction is spontaneous O ASsurr = -297 J K-¹ mol-1, reaction is not spontaneous

A reaction has values ΔS = 72.3 J K mol-1 and ΔH = 47.0 kJ mol-1. At what temperature (in °C) will this reaction become spontaneous?

1. On the basis of your experience, predict which of the following reactions are spontaneous. 1) NaCl(s)→→ NaCl(/) at 25 °C 2) 2 NaCl(s)→→ 2 Na(s) + Cl₂(g) 3) CO2(g) → CO2(s) at 25 °C 4) CO2(g) → C(s) + O2(g) 5) H₂O(s)→ H₂O() at 25 °C a) 1, 2, and 3 b) 1, 2, and 4 c) 3 and 5 d) 3 e) 5

The vaporization of compound A is described by the following chemical equation. A(1) A(g) AH vap (78.97 °C) = 37.87 kJ/mol Calculate the entropy of vaporization, A.Svap, for A(1) at 25.0 °C given that the boiling point of A is 78.97 °C, and the molar heat capacity of A(1) is 114.29 J/(mol K). Assume that the molar heat capacity of A(g) is 55.9% of that of A(1). ASvap = Calculate the standard enthalpy of vaporization, AHvap, for A(1) at 25.0 °C. AH vap = Calculate tl AG'vap = x10 TOOLS of vaporization, AGvap, at 25.0 °C. Determine the equilibrium constant K for the va 1970ea J. mol-1. K-1 kJ/mol kJ/mol

A reaction has a ΔH of -87.36 kJ and a ΔS of -175.3 J/K. At what temperature (in K) does the reaction become spontaneous?     626.4 K     This reaction is always spontaneous     498.3 K     434.6 K     This reaction is never spontaneous

The enthalpy and entropy changes for a reaction at 298 K are ∆H = 46 kJ and ∆S = 190 J/K. Which of the following best describes this reaction A) The reaction is spontaneous and driven by favorable changes in the enthalpy and entropy. B) The reaction is not spontaneous because heat is absorbed. C) The reaction is not spontaneoius but could be spontaneous at a higher temperature. D) The reaction is spontaneous and driven by the favorable entropy change.