Consider the following reaction: AICH Toluene MECOCI Me- COME UCI How are these products being formed? Show all appropriate steps (mechanism) in this reaction. Show all appropriate arrows!!!

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How are these products being formed? Show steps and arrows
### Detailed Mechanism of Friedel-Crafts Acylation Reaction

**Consider the following reaction:**

\[ \text{Toluene} + \text{MeCOCl} \xrightarrow{AlCl_3} \text{Me} - \underset{\text{Acyl group}}{\overset{\text{Acylated toluene}}{\text{COMe}}} + \text{HCl} \]

**Question:**
How are these products being formed? Show all appropriate steps (mechanism) in this reaction. **Show all appropriate arrows!!!**

### Explanation:

This reaction is a Friedel-Crafts acylation, an important method in organic chemistry for introducing an acyl group into an aromatic ring. The following steps outline the detailed mechanism:

1. **Formation of the Acylium Ion:**
   - The acyl chloride (MeCOCl, where Me = CH₃) reacts with aluminum chloride (AlCl₃), a Lewis acid. This interaction polarizes the carbonyl group (C=O), leading to the formation of the acylium ion (MeCO⁺) and an AlCl₄⁻ ion.
     \[
     \text{MeCOCl} + \text{AlCl}_3 \rightarrow \text{MeC}^+O + \text{AlCl}_4^-
     \]

2. **Generation of the Electrophile:**
   - The acylium ion (MeCO⁺), generated in the previous step, serves as the electrophile that will attack the aromatic ring in toluene.

3. **Electrophilic Attack on Toluene:**
   - Toluene, an aromatic compound, acts as a nucleophile due to the delocalized π-electrons in the benzene ring. The acylium ion attacks the aromatic ring, creating a sigma complex (arenium ion).
     \[
     \chemfig{*6(=-(*5(=-([-H]-Me)-=))-=)}
     \rightarrow \chemfig{*6(-*5(-=(-(CO-Me)-\chemfig{AlCl_3})))}
     \]

4. **Restoration of Aromaticity:**
   - In the final step, the proton (H⁺) that was initially attached to the carbon atom at the site of electrophilic attack is removed. This
Transcribed Image Text:### Detailed Mechanism of Friedel-Crafts Acylation Reaction **Consider the following reaction:** \[ \text{Toluene} + \text{MeCOCl} \xrightarrow{AlCl_3} \text{Me} - \underset{\text{Acyl group}}{\overset{\text{Acylated toluene}}{\text{COMe}}} + \text{HCl} \] **Question:** How are these products being formed? Show all appropriate steps (mechanism) in this reaction. **Show all appropriate arrows!!!** ### Explanation: This reaction is a Friedel-Crafts acylation, an important method in organic chemistry for introducing an acyl group into an aromatic ring. The following steps outline the detailed mechanism: 1. **Formation of the Acylium Ion:** - The acyl chloride (MeCOCl, where Me = CH₃) reacts with aluminum chloride (AlCl₃), a Lewis acid. This interaction polarizes the carbonyl group (C=O), leading to the formation of the acylium ion (MeCO⁺) and an AlCl₄⁻ ion. \[ \text{MeCOCl} + \text{AlCl}_3 \rightarrow \text{MeC}^+O + \text{AlCl}_4^- \] 2. **Generation of the Electrophile:** - The acylium ion (MeCO⁺), generated in the previous step, serves as the electrophile that will attack the aromatic ring in toluene. 3. **Electrophilic Attack on Toluene:** - Toluene, an aromatic compound, acts as a nucleophile due to the delocalized π-electrons in the benzene ring. The acylium ion attacks the aromatic ring, creating a sigma complex (arenium ion). \[ \chemfig{*6(=-(*5(=-([-H]-Me)-=))-=)} \rightarrow \chemfig{*6(-*5(-=(-(CO-Me)-\chemfig{AlCl_3})))} \] 4. **Restoration of Aromaticity:** - In the final step, the proton (H⁺) that was initially attached to the carbon atom at the site of electrophilic attack is removed. This
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