College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Consider the following image, point P is located on the x axis with coordinates (X, 0). Two positive charged particles are on the y-axis, ad and b apart respectively from the point of origin (0, 0). Lower the electric field equation for each component of the electric field at point P
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- We have calculated the electric field due to a uniformly charged disk of radius R, along its axis. Note that the final result does not contain the integration variable r: R. Q/A 2€0 Edisk (x² +R*)* Edisk perpendicular to the center of the disk Uniform Q over area A (A=RR²) Show that at a perpendicular distance R from the center of a uniformly negatively charged disk of CA and is directed toward the disk: Q/A radius R, the electric field is 0.3- 2€0 4.4.1barrow_forwardUse the figure below. There is a point charge of 6.20 microCoulombs inside a spherical conducting shell with inner radius a=3.10 m and outer radius b=3.35 m. There is a total charge of 15.50 microCoulombs on the spherical shell. What is the electric field at r=2.85 m from the point charge (ie inside the shell)? (Treat + as away from the point charge and negative as toward the point charge. Answer in N/C).arrow_forwardAssume a uniformly charged ring of radius R and charge Q produces an electric field E at a point Pon its axis, at distance x away from the center of the ring as in Figure a. Now the same charge Q is spread uniformly over the circular area the ring encloses, forming a flat disk of charge with the same radius as in Figure a. How does the field Eick produced by the disk at P compare with the field produced by the ring at the same point? O O Ek Ering O impossible to determinearrow_forward
- Consider the following image, point P is located on the x axis with coordinates (X, 0). Two positive charged particles are on the y-axis, ad and b apart respectively from the point of origin (0, 0). Draw each component of the electric field at point P?arrow_forwardDraw the graph and show complete solutionsLet: q1 = +8 μC , at the originq2 = +6 μC , 6 meters to the right of the originq3 = -86 μC , 8 meters above q2q4 = -0.75 μC , 8 meters above the origin Find the magnitude and direction of the total electric force and total electric field at q3.arrow_forwardProblems 4-5 refer to the following diagram and situation. A point charge (with charge Q) at the end of an insulating cord is observed to be in equilibrium in a uniform horizontal electric field of when the pendulum's angle with the vertical is 0 = 38.6°, is as shown in the Figure. The electric field is to the right and the strength of the electric field is 9500 N/C. The mass of the point charge is m = 0.0200 kg and the acceleration due to gravity is 9.8 m/sec². Problem 4: What is the tension on the cord? a. 0.251 N Problem 5: What is the charge Q? a. (1.65 x 10-5)C E b. 0.451 N b. (3.65 x 10-5)C 0 Q m c. 0.651 N C. (5.65 x 10-5) C d. 0.851 N d. (7.65 x 10-5)Carrow_forward
- A linear charge begins at X=X, and it continues until infinity, If the linear density of the charge is Xo 2 = 1o calculate the electric field at the originarrow_forward-2Q + 2Q a P -x direction X A semicircle of radius a is in the second and third quadrants, with the center of the curvature at the origin. Positive charge +2Q is distributed uniformly around the bottom half of the semicircle, and negative charge -2Q is distributed uniformly around the top half of the semicircle as shown in the figure. What is the direction of the net electric field at the origin produced by this distribution of charge?arrow_forwardA small plastic ball of mass m = 3.00 g is suspended by a string of length L = 17.0 cm in a uniform electric field, as shown in the figure below. If the ball is in equilibrium when the string makes a ? = 17.0° angle with the vertical as indicated, what is the net charge on the ball? answer in ucarrow_forward
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