Consider the following function. def modexp3(base, exponent, p): if exponent == 8: return 1 val= base currentExponent = 1 while currentExponent exponent/2: val = (vale*2) * p current Exponent current Exponent 2 remainderExponent = exponent current Exponent return (val modexp3(base, remainderExponent, p) p) 1. Run through what happens when modexp3 (5, 48,7) is called. 2. Do you notice any work being duplicated? Can you think of a way to modify the function to remove this redundancy? (You don't have to implement it. Just think about it and explain in words what you should do).

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Consider the following function.
def modexp3 (base, exponent, p):
if exponent 0:
return 11
val= base
currentExponent = 1
while current Exponent <= exponent/2:
val = (vale*2) * p
current Exponent currentExponent * 2
remainderExponent = exponent current Exponent
return (val modexp3 (base, remainderExponent, p) p)
1. Run through what happens when modexp3 (5, 48,7) is called.
2. Do you notice any work being duplicated? Can you think of a way to modify the function to remove this redundancy? (You don't have to
implement it. Just think about it and explain in words what you should do).
Transcribed Image Text:Consider the following function. def modexp3 (base, exponent, p): if exponent 0: return 11 val= base currentExponent = 1 while current Exponent <= exponent/2: val = (vale*2) * p current Exponent currentExponent * 2 remainderExponent = exponent current Exponent return (val modexp3 (base, remainderExponent, p) p) 1. Run through what happens when modexp3 (5, 48,7) is called. 2. Do you notice any work being duplicated? Can you think of a way to modify the function to remove this redundancy? (You don't have to implement it. Just think about it and explain in words what you should do).
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