Consider the following figure. (Assume R1 = 20.0 Ω, R2 = 8.0 Ω, and V = 18 V.) (a) Find the current in each resistor of the figure above by using the rules for resistors in series and parallel. 8.0 Ω A 20.0 Ω A 24 Ω A (b) Write three independent equations for the three currents using Kirchoff's laws: one with the node rule; a second using the loop rule through the battery, the 8.0-Ω resistor, and the 24.0-Ω resistor; and the third using the loop rule through the 20.0-Ω and 24.0-Ω resistors. Solve to check the answers found in part (a).

Using Kirchhoff's rules, find the following. (&₁ = 70.2 V, &2 = 61.4 V, and 83 78.6 V.) = 4.00 ΚΩ = = b = Es a IR3 2.00 ΚΩ (a) the current in each resistor shown in the figure above X IRI Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA X R₂ R₁ E₂ R3 f 3.00 ΚΩ d E₂ 3 R2 Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA X Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA

Problem2:. Consider the circuits shown below. (a) Write the equation for current using the junction rule. (b) Write two equations using loop rule (c) Use these equations to find I₁, I2, and I3? (b) What is the power dissipated across each resistor (1²R)? V₁ = 24 V 12 R₂ = 62 R₁ = 80 ½ 13 R₂=402 + ₂10 V

Consider the circuit shown in the figure, where ₁ = 21.7 V, E₂ submitted in WebAssign.) &₁ نه كنا 13 = || = = = E₂ = + = ww R i (a) What is the current (in A) in each resistor? I₁ 0.46 X Apply Kirchhoff's junction and loop rules to the circuit to find three separate equations in terms of the unknown currents, and solve your system for I₁, I2, and/or 13. A 28.0 Ω 12.0 Ω 1₁ A A 1₂ (b) What is the power (in W) delivered to each resistor? P₁ W 1 P₂ W P3 W Is = 15.3 V, and R (c) What is the total power (in W) supplied by both batteries? W = 12.00. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers