Consider the following database schema for University Library database. A student can borrow many books and a given book can be porrowed by any student if it is available in the library. For each borrowing, the borrowing and return dates are registered in the database. Student (SID: long, CPR:long (unique), Name:string, tel:number, major:String, gender:Character { 'F' or 'M'}) Book (ISBN:long, Title:string (unique), Author:string) Borrowedltems(stSID:long, booklSBN:long, serialNoint (unique), BorrowingDate:date, ReturnDate:date) Write SQL statements to: 1. List ISBN, Title, Author of all books that include the word 'Database' in their titles in a descending order of ISBN. 2. List SID, Name, and Major of all female students doing major in 'CS' and their name starts with 'S'.
Q: QUESTION 3 Consider the following database schema for a library. Book (BookiD:int,…
A: Answer :-- True
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Q: QUESTION 3 Consider the following database schema for a library. Book (BookID:int,…
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Q: A QUESTION 6 Consider the following database schema for a library. Book (BookID:int,…
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Q: QUESTION 6 Consider the following database schema for a library. Book (BooklD:int,…
A: The answer is True.
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Q: QUESTION 2 Consider the following database schema for a library. Book (BookID:int…
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Q: Consider the following database schema for a library. Book (BookID:int, BookTitle:string(unique),…
A: Here the bookid is primary key, and therefore in building a borrowing-record it used as a…
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A: No, It Is Not Possible to have a Borrowing-Record with an unknown CustomerCPR.
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Q: QUESTION 6 Consider the database schema below. Fruit (ID: integer, Name: String (unique)) Vitamin…
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Q: QUESTION 5 Consider the following database schema for a library. Book (BookID:int,…
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- branch(branchhame, branch+citysassets} customer (HD, Customer name, customer street, customer city) loan loan number branch_name, amounty borrower(ID; loan_number account (account_number, branch name, balance)e depositor (HDs account number)- Figure le Consider the bank database in Figure 1, where the primary keys are underlined. Each branch might have many loans or accounts, associated with borrowers or depositors, respectively. Construct the following SQL queries for this relational database. 1. Find the name of each branch that has at least one customer who has an account in the bank and who lives in the "Harrison" city. Make sure each branch name only appears once. 2. Find the ID of each customer who lives on the same street and in the same city as customer "12345". (1) Please use "tuple variables". e (2) Please use "derived relations" or “with". 3. Find the ID of each customer of the bank who has an account but not a loan. 4. Find the total sum of all loan amounts for each branch…FUNDAMENTAL DATABASE SUBJECT: Case: A car wash owner wants to monitor the inventory of products and sales of the business. Create a database design in preparation for a system development that would: Store and monitor the supply of products; The number of vehicle washed by a car wash boy. Vehicles can be classified according to its type (motorcycle, van, bus, etc.). The list of vehicles washed by a car wash boy can be monitored. Salary per employee and the vehicles washed can be retrieved. Car wash history per vehicle can be check also. We already Identified the possible tables, so your task will be: 1. Add data on the tables (assume that this is not normalized yet) 2. reflect on the table and follow the normalization steps base on the rules. 3. normalize its table 4. add all table in one document (lucidchart/google docs), should have relationships and cardinality. 5. make sure that it is in highest normal form, highest will be BCNF (if needed).//Need typed version please You are working with a database that stores information about suppliers, parts and projects. The Supply relation records instances of a Supplier supplying a Part for a Project. The schema for the database used in this question is as follows: ( primary keys are shown underlined, foreign keys in bold). SUPPLIER (SNo, SupplierName, City) PART (PNo, PartName, Weight) PROJECT (JobNo, JobName, StartYear, Country) SUPPLY (SNo, PNo, JobNo, Quantity) Provide relational algebra (NOT SQL) queries to find the following information. NOTE: You can use the symbols s, P, etc or the words ‘PROJECT’, ‘RESTRICT’ etc . do not need to try to make efficient queries – just correct ones. Where you use a join, always show the join condition. List the name of any part that was not used on a project that commenced in 2020. List the name of any part that has been supplied to all projects that commenced in 2020.
- Data base systmes: Design an ER schema diagram for a sport league database to keep track of the teams and games of it. The database is organized into teams. Each team has a unique name, a unique number, and particular colors. A team may have several colors. Each team plays several games. It is desired to keep track of the result of each game. A team has a number of players, not all of whom participate in each game. Each player has a unique name, a unique number, and a particular position. It is desired to keep track of the players participating in each game for each team, the performance they played in that game, and the time played by each player in each game.struct student { char name[20]; char studentID[10]; char phonenum [9]; char advisor [20]; float gpa; } Operations needed: addnewStudent { purpose: to create a new student in the database input: name, studentID.phonenum,advisor.gpa output: none } Name another operation besides add that we could use for our student data structure.J SHORTAND NOTATION FOR RELATIONAL SQL TABLES Notation Example Meaning Underlined A or A, B The attribute(s) is (are) a primary key Superscript name of relation AR or AR, BR The attribute(s) is (are) a foreign key referencing relation R As an example, the schema R(A, B, C, D, ES) S(F, G, H) corresponds to the following SQL tables: CREATE TABLE R ( A <any SQL type>, B <any SQL type>, C <any SQL type>, D <any SQL type>, E <any SQL type>, PRIMARY KEY(A), FOREIGN KEY (E) REFERENCES S(F) ); CREATE TABLE S ( F <any SQL type>, G <any SQL type>, H <any SQL type>, PRIMARY KEY(F)) EXERCISE Consider the following relational schema, representing five relations describing shopping transactions and information about credit cards generating them [the used notation is explained above]. SHOPPINGTRANSACTION (TransId, Date, Amount, Currency, ExchangeRate, CardNbrCREDITCARD, StoreIdSTORE) CREDITCARD (CardNbr, CardTypeCARDTYPE, CardOwnerOWNER, ExpDate, Limit)…
- c# Create a small Sports database with two tables: Team and Athlete. The Team table should include fields for the type of team (e.g., basketball), coach's name (both last and first), and the season the sport is most active (S for spring, F for Fall, or B for both). The Athlete table should include fields for student number, student first and last names, and type of sport. Use the same identifier for type of sport in both tables to enable the tables to be related and linked. Populate the tables with sporting teams from your school. Write a C# program that displays information about each team, including the names of the athletes. The data base we have provided to us just need to know how to program it in with the other guidelines given.SQL and Relational Algebra Related question There is a Company Database that manages the data of employee, department and project. The relational schemas are as follows: EMPLOYEE (Gname, Fname, Employee_id, Bdate, Gender, Salary, Dno). The attribute means: given name, family name, employee id, birthdate, gender, salary, the department number in which the employee works. Each employee has a unique employee id, and can join in projects that in different department. DEPARTMENT (Dno, Dname, Manager_id, Dloc). The attribute means: Department number, department name, department manager id, department location. The department manager is a type of the employee, thus the Manager_id is a foreign key that references the Employee_id in EMPLOYEE table. PROJECT (Project_id, Pname, DNO). The attribute means: project id, project name, department number of the department that the project belongs to. Part of the data in the relations are as follows: Table1 EMPLOYEE Gname Fname Employee_id…The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. List all copies of the book title “Lord of the Rings” that are available for borrowing. List the names of borrowers who currently have the book title “Lord of the Rings” on loan. List the names of borrowers with overdue books.
- The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. Formulate the following queries in relational algebra and tuple relational calculus: 5.27 List all copies of book titles that are available for borrowing. 5.28 List all copies of the book title “Lord of the Rings” that are available for…The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. Formulate the following queries in relational algebra and tuple relational calculus: a. List all book titles. b. List all borrower details. c.List all book titles published in the year 2012. d. List all copies of book titles that are…The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. a. List all copies of the book title “Lord of the Rings” that are available for borrowing. b. List the names of borrowers who currently have the book title “Lord of the Rings” on loan. c. List the names of borrowers with overdue books.