Consider the following data [Figure]. Suppose round robin scheduling is applied on the given data with time quantum=Floor (XX % 3) units. It is also given that scheduling of a process or context switch will take 1 unit of time. What is the completion time and turnaround time of process P4? Where XX is the last two digits of your roll number. XX=18

To not let any process wait longer than 500 ms, a system developer programs the Round Robin procedure with a dynamic time quantum size. With ‘n’ processes ready, the time quantum Q is set to 500 ms/n. What do you think of this scheduling strategy? (In which situations is this strategy feasible, and when is it not? Are there edge cases?) Explain your reasoning.

Process PI P2 P3 P4 P5 Buast time 2 1 8 4 5 Priority (2*xx) %5 (2xxx) 5 (2*XX) 0/0 5 (2*XX) do 5 (2*xx) do 5 ✓ 11 Value of XX is 5 All processes Arrives at time + = 0 ms. Draw the Gantt chart for priority scheduling (A larger priority number implies higher priority)

please do part c and d! i got 3 diff answers when i asked experts on bartleby. now i am confused.

Q-1: Draw the Shortest Remaining Time First (with Preemption) and Round Robin (no Preemption) Gannt chart for the following processes. Calculate average wait time for each algorithm using the processes data below. Round Robin uses a time quanta of 3. Process Number PO P1 P2 P3 P4 P5 Arrival Time Burst Time to Complete 10 2 0 3 4 13 25 26 6 10 1 3

Table 1. 4 processes arriving shown in Operating System Scheduling PDF for Shortest Job Next, non- preemptive Process Arrival Times Execution Times Service Times sequence Wait Times calculations PO 0 12 P1 21 9 P2 41 6 P3 6 3 Total wait time = ? Here the 4 processes of the PDF are repeated in Table 1, with arrival times changed to 0, 2, 4, and 6 respectively. Also, the execution times are changed to 12, 9, 6, and 3. You will be asked to fill table 1 with the numbers like the service times (when is each process serviced), the sequence of executions of these 4 processes in part (a) and part (b) below. Also, you will compute the total wait time. Note for FCFS, it is 1, 2, 3, 4 for P0, P1, P2, and P3; • for the SJN or Shortest Job Next with non-preemptive, PO is #1, P1 may not be #2; for SRT, or shortest remaining time, the preemptive version of SJN, PO is #1, but after 2 time units when P1 comes, P1 kicks out PO since its execution time is 4 < 9- 2 = 7; and P1 may be preempted by P2 later…

Eight batch jobs arrive almost at the same time in the following order: I₁, 2, ..., II8. The table below contains their running times and priorities: Job П1 П2 П3 П4 П П П П Running time (in min) 4 5 5 10 8 10 7 Priority 1 7 5 2 8 6 4 3 The highest priority is 1. For each of the following scheduling algorithms, determine the order of execution of processes and the mean process turnaround time: (a) priority scheduling; (b) first-come, first-served; (c) shortest job first. Scheduling is non-preemptive.

Consider the following snapshot of a system: Allocation Маx Available ABCD ABCD ABCD PO 2001 4212 3321 P1 3121 5252 P2 2103 2316 P3 1312 1424 P4 1432 3665 a. Illustrate that the system is in a safe state by demonstrating an order in which the processes may complete.

Note: this question is related from operating system subject. Q:By Round Robin (time quantum= 3) show the scheduling order of the processes using a Gantt chart in the following data. Also b) What is the turnaround time for each process? c) What is the waiting time for each process? d) What is the response time for each process?   Process Burst Arrival P1 30 0 P2 25 40 P3 20 50 P4 12 75

Describe the impact that "changing time quantum" has on the process execution of Round-Robin scheduling by first explaining what is meant by the phrase "Time Quantum."