Consider the following assembly language code: LCO: string "answer %d\n" text globl main type main, @function main: pushq %rbp movq %rsp, %rbp subq $16, %rsp
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A: The answer is....
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A: This answer is given below
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A: Summary: -Hence, we have discussed all the point.
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A: Hi Dear!! Please give positive feedback!!!
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- Computer Science #include<cmath>#include<stdio.h>__global__voidprocess_kernel1(float *input1,float *input2,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = sinf(input1[index]) + cosf(input2[index]);}__global__voidprocess_kernel2(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = logf(input[index]);}_global__voidprocess_kernel3(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x *…convert this code to java language /* OPERATING SYSTEMS LAB PROJECT* AKASH JAIN* 179303013* DESIGNING A VIRTUAL MEMORY MANAGER*/ #include<stdio.h>#include<stdlib.h>#include<string.h> const int VM_SIZE=256;const int PAGE_SIZE=256;const int TLB_SIZE=16;const int MM_SIZE=256; int main(int argc, char* argv[]){FILE *fd;if(argc<2){printf("NOT ENOUGH AGRUMENTS\n EXITING\n");return 0;}fd=fopen(argv[1],"r");if(fd==NULL){printf("ERROR OPENING FILE\n FILE FAILED TO OPEN\n");return 0;}char *value=NULL;size_t len=0;ssize_t read;long long page_no,offset,page_table,totalhits=0,fault=0,pages=0;int qp=0; //to maintain the queue positionint physicalad=0,frame,logicalad;int tlb[TLB_SIZE][2];int pagetable[PAGE_SIZE]; memset(tlb,-1,TLB_SIZE*2*sizeof(tlb[0][0]));memset(pagetable,-1,sizeof(pagetable));int mask=255,mask1=62580,i,hit;while((read=getline(&value,&len,fd))!=-1){pages++;//get page number and offset from logical…Please calculate the object codes of the following Program with Multiple Program Blocks source statement. Line Loc/BLK Source Statement 60 STA LENGTH 65 JSUB WRREC 220 JEQ WLOOP 225 LDCH BUFFER,X Opcode STA=0Ch JSUB=48h JEQ=30h LDCH=50h
- Write assembly language codes that will display the output given below. Clear the entire screen and display it at row 1, column 1. You may use any attribute. Use functions/services and loop operation. NOTE: Do not use "print string" function. 0123456789 012345678 01234567 0123456 012345 01234 0123 012 01 0Q4 What is the compiled MIPS assembly code for the following C code? CMassoS no ouoolidonA seugmoto taeT onlinc int x = 0; int y = 1; int z; = sum(x, y);aluoineq aol aoonaupsa ebco owi neewed abbibeb at gnivil al engisob 1eoligmoo A TO x = X-z; eloet onhwollot orlt beilgque evert aengiaeb eiawons int sum(int g, int h) sesio noilounten rtoas 1ot 19 int f; f = (g + h); return f; ealbyo lo) 19 Snoilounteni eq aboo owt gnhebienoo ei nethw 1eligmoo ertt inemetela opeupnst level-rigirl 1aluoiheq s 1 be initialized at the beginning of the code. The argument of sum procedure should be saved in $a0 and $a1. The result f should be saved in $v0. Your answer must include your own comments for the MIPS code. Students must use the instructions studied in the class (in the slide) for programming.rt eetuoexe eoneupee ebos ra Setest ed liw soneupee eboo rts feonsupee riose ot 190 spvA er) ei .22e00g noitsluolso ert ebuloni taurm newans nuoy ((Write an assembly language program that corresponds to the following C program: int num;int main () { scanf("%d", &num); num = num / 16; printf("num = %d\n", num); return 0; i just need the assembly language code for this program cna you help me please
- Find the register values:.datamyBytes BYTE 12h,34h,56h,78h.codemov ax,WORD PTR [myBytes] ; AX = ?mov ax,WORD PTR [myBytes+2] ; AX = ?mov eax,DWORD PTR myBytes ; EAX = ?Write a Pep/9 assembly language program that corresponds to the following C program: int num1; int num2; int main () { scanf("%d %d", &num1, &num2); printf("%d\n%d\n", num2, num1); return 0; }Translate the following C program into Pep/9 assembly language:#include <stdio.h>int main () {int num1;int num2;scanf("%d", &num1);num2 = -num1;printf("num1 = %d\n", num1);printf("num2 = %d\n", num2);return 0;} please explain and provide c
- Translate the following C program to Pep/9 assembly language. #include <stdio.h> int myAge; void putNext(int age) {int nextYr;nextYr = age + 1;printf("Age: %d\n", age);printf("Age next year: %d\n", nextYr);} int main () {scanf("%d", &myAge);putNext(myAge);putNext(64);return 0;}Convert this code to RISC-V 64 gcc assembly language #include <stdio.h> char inputText[] = "babibabbbiiibabibiba";char pattern[] = "bi";const int patternSize = 2;const int inputSize = 20; int main(){ int lps[patternSize]; lps[0] = 0; int len = 0; int i = 1, j = 0; while (i < patternSize) { if (pattern[i] == pattern[len]) { len++; lps[i] = len; i++; } else { if (len != 0) { len = lps[len - 1]; } else { lps[i] = 0; i++; } } } i = 0; while (i < inputSize) { if (pattern[j] == inputText[i]) { j++; i++; } if (j == patternSize) { printf("Found pattern at index %d \n", i - j); j = lps[j - 1]; } else if (i < inputSize && pattern[j] != inputText[i]) {…MIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.