Consider the figure shown below. Find the voltage (V) at node 1. V1 10V Qu'e 15 V شمشه O 12 V O 16 V O 14 V R2 12
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- for the circuit shown below If v_in=5 sin2m10t then corner frequency will be ......Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 vinConsider the circuit below: Simplify the circuit and write the super position circuits for I1, 12, and 13 2 AZ45° 1220 v 4 AZ0° O 20 3 VZ-90°sohw circuit diagram and step by step solution pls
- 4. Application of Complex Number Determine the values of L and C that will make the equivalent impedance across the source be a pure resistance of 250 ohms. Vs 60Hz 1000 LZVO A VM ll l Ciassroo docs.google.com a Q1 For the following circuit diagram, 1 is .......... 50 15 V 12V 40 50 I2 70 60 90 12 a 4 A 1 O -1 احمد عصام احمد 8:00- äc lul 21.04.20 O DBoth the electric and magnetic field can produce force. In your opinion why Fm involves cross product and Fe does not? * QQ Fe 4TE,R 2 F = Qux B = Qu×B m The force acts along the line joining the charges for Fe The direction of magnetic force acting on any charged particles Q moving with a uniform velocity U in a magnetic field B is orthogonal with U and B Two like charges repel one another, whereas two charges of opposite polarity attract. Its strength is directly proportional to the product of the magnitudes of the two charges and inversely proportional to the square of the distance between them.
- or the coupled circuit shown in Figure 3, find the voltage across the capacitor of -j1092 reactance with Vi=1020° V and V2=10290° V? j20 www www 50 50 V₁ 5 100 Figure 3 5 V₂ID 62200072 Please solve right nowApplication: Construct the circuit in figure. R= 2,2KN, L = 1 mH, and C= 10 nF. L Necesssary Formulae: 1 Xc 2.π.f.C X.-2. π.f. L By using the formulea perform the calculations of Xc and XL then fill the table. f (Hz) Xc XL 50000 60000 70000 80000 90000 100000 110000 120000 130000 140000