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Consider the feedback control system block diagram in Fig.1

Consider the feedback control system block diagram in Fig.1

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Use Where K>1

Consider the feedback control system block diagram in Fig.1 Investigate closed loop stability for Gc(s) = K(s + 2) and G(s) = 1/(s+3)(s-2), for the two cases where K = 1 and K = 3., the system is: O a. O b. O C. O d. R(s) Controller G,(s) Process G(s) Fig.1 b. Stable for K = 2 and unstable for K = 4 a. Unstable for K = 2 and unstable for K = 4 d. Unstable for K = 1 and stable for K = 4 c. Stable for K = 2 and stable for K = 4
Transcribed Image Text:Consider the feedback control system block diagram in Fig.1 Investigate closed loop stability for Gc(s) = K(s + 2) and G(s) = 1/(s+3)(s-2), for the two cases where K = 1 and K = 3., the system is: O a. O b. O C. O d. R(s) Controller G,(s) Process G(s) Fig.1 b. Stable for K = 2 and unstable for K = 4 a. Unstable for K = 2 and unstable for K = 4 d. Unstable for K = 1 and stable for K = 4 c. Stable for K = 2 and stable for K = 4
Utilizing the Routh-Hurwitz criterion to determine whether the following polynomials are: P₁(s) = s² + s³ + s² + s + K = 0 P₂(s) = s5 +2sª + 2s³ + 4s² + 11s + 10 = 0 a. O b. 0 с. O d. d. p₁(s) is unstable, p₂ (s) is unstable b. p₁(s) is unstable, p₂ (s) is stable a. p₁(s) is stable, p₂ (s) is stable c. p₁(s) is stable, p₂ (s) is unstable
Transcribed Image Text:Utilizing the Routh-Hurwitz criterion to determine whether the following polynomials are: P₁(s) = s² + s³ + s² + s + K = 0 P₂(s) = s5 +2sª + 2s³ + 4s² + 11s + 10 = 0 a. O b. 0 с. O d. d. p₁(s) is unstable, p₂ (s) is unstable b. p₁(s) is unstable, p₂ (s) is stable a. p₁(s) is stable, p₂ (s) is stable c. p₁(s) is stable, p₂ (s) is unstable
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