Consider the electrophilic aromatic substitution reaction shown and draw the structure of the resulting organic product. NH2 ولا + Ο Ν כ C NaNO2, HCl, 2°C 8། N=N H C N S F P ·N Cl
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- An important step in one synthesis of carboxylic acids is the deprotonation of diethyl malonate and its alkyl-substituted derivative: Base CH;CH2O OCH,CH3 CH;CH,0 OCH2CH3 H2 Diethyl malonate Base CH;CH,0 °C `OCH,CH3 CH;CH,O OCH,CH3 R Alkyl substituted diethyl malonate NaOH can deprotonate diethyl malonate effectively, but NaOC(CH3)3 is typically used to deprotonate the alkyl-substituted derivative. Explain why.All electrophilic aromatic substitution reactions occur via a two-step mechanism: addition of the electrophile to form a resonance-stabilized carbocation, followed by deprotonation by a base. In the step shown below, loss of a proton to form the substitution product was drawn using the resonance structure with the + 1 formal charge at the ortho position to the carbon bonded to the electrophile. Redraw the step shown with the other two resonance structures and use curved arrows to show how these other two resonance structures can be converted to the substitution product by removal of a proton with the base shown. Part: 0/2 Part 1 of 2 H :CI-AICI, Draw the mechanism that generates the final substitution product with the +1 formal charge at the para position. Cl HC1 AICI3Draw a Lewis structure of sodium ethyl mercaptide (NaSC2H5), showing all relevant lone pairs and formal charges. Based on the structure you drew, do you expect that it would act as a good nucleophile? Do you expect it to act as a strong base?
- 5A In the following reactions, mixtures of alkenes and ethyl ethers are formed. Draw their structures. Explain which is or are likely to be the main product(s) in each reaction. In case of formation of two isomers of alkenes, explain which is formed in greater proportion CH3 ofi H3C- -Br CH3 EtOHThe reaction of ozone with 2-butene leads to -10 formation of aldehyde + ketone 0 aldehyde + alcohol 0 two molecules of carboxylic acid 0C=CH H20, H2SO4 H9SO4 CH3 Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H-OH HO: Hjö: C=CH c=CH Hö Hg Hg
- Write down the common (not IUPAC) names of the organic molecules that would be released if this molecule were hydrolyzed: CH,—O—C—(CH2)—CH=CH-CH,—CH=CH—(CH2) — CH3 CH-0- -(CH2)–CH=CH(CH2)CH3 O CH,—O-C=(CH2)=CH=CH(CH2)—CH3 Separate each name with a comma and a space. You will find useful information in the ALEKS Data resource. type your answer...Fill in the table with the partial charges of the atoms. The atoms are numbered with the following scheme with respect to the substituent on the aromatic ring. x c/ 3. | H./ Atom Chlorobenzene Nitrobenzene Aminobenzene C2 Ca Which substituent results in a ring atom with the greatest positive charge (smallest negative charges)? What is the mechanism that causes this pattern of electron distribution on the aromatic ring? Diagram the mechanism. Which substituent results in a ring atom with the least positive charge (largest negative charges)? What is the mechanism that causes this pattern of electron distribution on the aromatic ring? Diagram the mechanism.5B In the following reactions, mixtures of alkenes and ethyl ethers are formed. Draw their structures. Explain which is or are likely to be the main product(s) in each reaction. In case of formation of two isomers of alkenes, explain which is formed in greater proportion CH3 CH3 H3C-C H -Br CH3 EtOH
- 12) Use the curved arrow formalism to show the movement of electron pairs in the following reaction and label each reactant as a nucleophile or an electrophile. CHÍNH CHỊCH, + CO Học Nha CH₂CH₂CI4-pyranone will readily undergo an acid-base reaction. Identify the reaction conditions that will result in the formation of an aromatic product. Then, draw the aromatic resonance product structure. Include all lone pairs in your structure. Ignore inorganic byproducts. H3O+Q2. Consider the nucleophilic substitution reaction between 3-chloro-3-methylpentane and the hydroxide ion: CI x + OH (a) Is the alkyl halide 1°, 2° or 3°? (b) Will the nucleophilic substitution reaction be S₁1 or S№2? (c) Give the substitution mechanism showing all full and partial positive and negative charges, electron movements using curved arrows.
