Consider the differential equation (a) Find 71, 72, roots of the characteristic polynomial of the equation above. T1, T2 = 1,2 (b) Find a set of real-valued fundamental solutions to the differential equation above. y₁ (t) = Y2 y₂ (t) = y(t) y" - 3y + 2y = 0. e^t = e^(2t) (c) Find the solution y of the the differential equation above that satisfies the initial conditions y(0) = -3, y' (0) = 4. M M Σ M
Consider the differential equation (a) Find 71, 72, roots of the characteristic polynomial of the equation above. T1, T2 = 1,2 (b) Find a set of real-valued fundamental solutions to the differential equation above. y₁ (t) = Y2 y₂ (t) = y(t) y" - 3y + 2y = 0. e^t = e^(2t) (c) Find the solution y of the the differential equation above that satisfies the initial conditions y(0) = -3, y' (0) = 4. M M Σ M
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 16E: Find the general solution for each differential equation. Verify that each solution satisfies the...
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![Consider the differential equation
(a) Find 11, 12, roots of the characteristic polynomial of the equation above.
T1, T2
y₂ (t)
=
y(t)
(b) Find a set of real-valued fundamental solutions to the differential equation above.
y₁ (t) =
=
1,2
=
y" - 3y + 2y = 0.
e^t
e^(2t)
M
M
(c) Find the solution y of the the differential equation above that satisfies the initial conditions
y(0) = -3,
y' (0) = 4.
M
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0695e04c-6177-4dae-ae8e-62e62853c8ae%2F8c98dacc-f6c2-4c66-acf0-a4ed4c361357%2Fd17echs_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the differential equation
(a) Find 11, 12, roots of the characteristic polynomial of the equation above.
T1, T2
y₂ (t)
=
y(t)
(b) Find a set of real-valued fundamental solutions to the differential equation above.
y₁ (t) =
=
1,2
=
y" - 3y + 2y = 0.
e^t
e^(2t)
M
M
(c) Find the solution y of the the differential equation above that satisfies the initial conditions
y(0) = -3,
y' (0) = 4.
M
M
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