Consider the circuit shown in Figure P6.51. The parameter values are R=10³ , C=2x10-6 F, and L=2×10-³ H. The voltage v₁ is a step input of magnitude 5 V, and the voltage v₂ is sinusoidal with frequency of 60 Hz and an amplitude of 4 V. The initial conditions are zero. Use MATLAB to obtain a plot of the current response i3 (t).

Note: The user has asked only about the MATLAB code for current i3.According to the question, for the given circuit as shown belowWhere,We need to provide the MATLAB code for the current in inductor.In the circuit,V1(t) = 5 V step input.V2(t) = Sinusoidal input of frequency 60 Hz, and magnitude 4 V.The MATLAB code for the current across the inductor is,1% Circuit parameters 2R = 1e3; % Resistance in ohms 3C = 2e-6; % Capacitance in farads 4L = 2e-3; % Inductance in henries 5 6% Voltage sources 7V1 = 5; % Step input voltage in volts 8V2_amplitude = 4; % Amplitude of sinusoidal input voltage in volts 9V2_frequency = 60; % Frequency of sinusoidal input in Hz 10 11% Laplace domain representation of the circuit 12s = tf('s'); 13H = (1/(R + s*L))*(1/(s*C)); 14 15% Step response for V1 16t = 0:0.001:0.1; % Time vector 17u = V1*ones(size(t)); % Step input 18[y1, ~] = lsim(H, u, t); 19 20% Sinusoidal response for V2 21t = 0:0.001:0.1; % Time vector 22u = V2_amplitude * sin(2*pi*V2_frequency*t); % Sinusoidal input 23[y2, ~] = lsim(H, u, t); 24 25% Total response 26y = y1 + y2; 27 28% Plotting 29figure; 30plot(t, y, 'LineWidth', 2); 31title('Inductor Current Response'); 32xlabel('Time (s)'); 33ylabel('Current (A)'); 34grid on; 35The plot of the current is,The required MATLAB code is,1% Circuit parameters 2R = 1e3; % Resistance in ohms 3C = 2e-6; % Capacitance in farads 4L = 2e-3; % Inductance in henries 5 6% Voltage sources 7V1 = 5; % Step input voltage in volts 8V2_amplitude = 4; % Amplitude of sinusoidal input voltage in volts 9V2_frequency = 60; % Frequency of sinusoidal input in Hz 10 11% Laplace domain representation of the circuit 12s = tf('s'); 13H = (1/(R + s*L))*(1/(s*C)); 14 15% Step response for V1 16t = 0:0.001:0.1; % Time vector 17u = V1*ones(size(t)); % Step input 18[y1, ~] = lsim(H, u, t); 19 20% Sinusoidal response for V2 21t = 0:0.001:0.1; % Time vector 22u = V2_amplitude * sin(2*pi*V2_frequency*t); % Sinusoidal input 23[y2, ~] = lsim(H, u, t); 24 25% Total response 26y = y1 + y2; 27 28% Plotting 29figure; 30plot(t, y, 'LineWidth', 2); 31title('Inductor Current Response'); 32xlabel('Time (s)'); 33ylabel('Current (A)'); 34grid on; 35

Answered: Consider the circuit shown in Figure P6.51. The parameter values are R=10³ , C=2x10-6 F, and L=2×10-³ H. The voltage v₁ is a step input of magnitude 5 V, and…

Introductory Circuit Analysis (13th Edition)

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ISBN: 9780133923605

Author: Robert L. Boylestad

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Only MATLAB code please

Consider the circuit shown in Figure P6.51. The parameter values are \( R = 10^3 \, \Omega \), \( C = 2 \times 10^{-6} \, \text{F} \), and \( L = 2 \times 10^{-3} \, \text{H} \). The voltage \( v_1 \) is a step input of magnitude 5 V, and the voltage \( v_2 \) is sinusoidal with a frequency of 60 Hz and an amplitude of 4 V. The initial conditions are zero. Use MATLAB to obtain a plot of the current response \( i_3(t) \).

**Figure P6.51:**

The diagram shows a series RLC circuit. It includes:

- A resistor (\( R \)) with a resistance of \( 10^3 \, \Omega \).
- An inductor (\( L \)) with an inductance of \( 2 \times 10^{-3} \, \text{H} \).
- A capacitor (\( C \)) with a capacitance of \( 2 \times 10^{-6} \, \text{F} \).

The circuit is powered by two voltage sources:
- \( v_1 \) (on the left side), which is a step input at 5 V.
- \( v_2 \) (on the right side), providing a sinusoidal input with a frequency of 60 Hz and amplitude of 4 V.

The currents \( i_1 \), \( i_2 \), and \( i_3 \) are shown at different points in the circuit, with \( i_3(t) \) being the current of interest to be plotted using MATLAB.

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