Consider the circuit shown in (Figure 1). Suppose that E = 11 V. Figure 20 Ω 60 Ω www LuwLiw Switch 1 of 1 40 Ω 10 Ω ▼ Part A What is the current through the battery when the switch is open? Express your answer with the appropriate units. μA H I = Value Units Submit Request Answer Part B What is the current through the battery when the switch is closed? Express your answer with the appropriate units. ΜΑ ? I = Value Units Submit Request Answer

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### Circuit Analysis Problem

#### Problem Statement:
Consider the circuit shown in **Figure 1**. Suppose that \( \mathcal{E} = 11 \, \text{V} \).

#### Diagram:
![Figure 1: Circuit Diagram](circuit_image.jpg)
- **Figure 1** shows a circuit with a voltage source (\( \mathcal{E} \)) of \( 11 \, \text{V} \).
- The circuit contains four resistors with the following resistances: \( 20 \, \Omega \), \( 40 \, \Omega \), \( 60 \, \Omega \), and \( 10 \, \Omega \).
- A switch is present in the circuit, connected such that it is in series with the \( 10 \, \Omega \) resistor and in parallel with the \( 40 \, \Omega \) resistor.

#### Questions:

**Part A:**
- What is the current through the battery when the switch is open?
- **Express your answer with the appropriate units.**

Input box for answer:
\[ I = \]
\[ \text{Value } \text{Units} \]

Submit Button: [Submit]

Request Answer Link: [Request Answer]

---

**Part B:**
- What is the current through the battery when the switch is closed?
- **Express your answer with the appropriate units.**

Input box for answer:
\[ I = \]
\[ \text{Value } \text{Units} \]

Submit Button: [Submit]

Request Answer Link: [Request Answer] 

---

### Explanation of Diagram:
**Figure 1** illustrates the configuration of the resistors within the circuit, clearly showing the position of the switch. When analyzing the circuit, consider the following:
- **Switch Open:** The \( 10 \, \Omega \) resistor is not part of the circuit path, and current flows only through the \( 20 \, \Omega \), \( 40 \, \Omega \), and \( 60 \, \Omega \) resistors.
- **Switch Closed:** The \( 10 \, \Omega \) resistor is added in parallel to the \( 40 \, \Omega \) resistor, changing the circuit's overall resistance and the current distribution.

Use Ohm’s Law ( \( V = IR \) ) and the rules for series and parallel circuits to determine the total resistance and the current.
Transcribed Image Text:### Circuit Analysis Problem #### Problem Statement: Consider the circuit shown in **Figure 1**. Suppose that \( \mathcal{E} = 11 \, \text{V} \). #### Diagram: ![Figure 1: Circuit Diagram](circuit_image.jpg) - **Figure 1** shows a circuit with a voltage source (\( \mathcal{E} \)) of \( 11 \, \text{V} \). - The circuit contains four resistors with the following resistances: \( 20 \, \Omega \), \( 40 \, \Omega \), \( 60 \, \Omega \), and \( 10 \, \Omega \). - A switch is present in the circuit, connected such that it is in series with the \( 10 \, \Omega \) resistor and in parallel with the \( 40 \, \Omega \) resistor. #### Questions: **Part A:** - What is the current through the battery when the switch is open? - **Express your answer with the appropriate units.** Input box for answer: \[ I = \] \[ \text{Value } \text{Units} \] Submit Button: [Submit] Request Answer Link: [Request Answer] --- **Part B:** - What is the current through the battery when the switch is closed? - **Express your answer with the appropriate units.** Input box for answer: \[ I = \] \[ \text{Value } \text{Units} \] Submit Button: [Submit] Request Answer Link: [Request Answer] --- ### Explanation of Diagram: **Figure 1** illustrates the configuration of the resistors within the circuit, clearly showing the position of the switch. When analyzing the circuit, consider the following: - **Switch Open:** The \( 10 \, \Omega \) resistor is not part of the circuit path, and current flows only through the \( 20 \, \Omega \), \( 40 \, \Omega \), and \( 60 \, \Omega \) resistors. - **Switch Closed:** The \( 10 \, \Omega \) resistor is added in parallel to the \( 40 \, \Omega \) resistor, changing the circuit's overall resistance and the current distribution. Use Ohm’s Law ( \( V = IR \) ) and the rules for series and parallel circuits to determine the total resistance and the current.
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