Consider the circuit shown below. Find V, (in V), V, (in V), and R, (in Q). (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) , = 4 A R, = 7 0 V1 ½ = 3 A 13 = 1 A R, = 7 Q R, = 7 0 s = 3 A I6 = 2 A R4 4 = 1 A R, = 7 0 V = V V2 = V RA = > > a

What are the expected readings of the following in the figure below? (R = 9.50 Q, AV = 6.50 V) A AV 10.0 N 5.00 N + R 4.50 V (a) ideal ammeter (Give your answer in mA.) (b) ideal voltmeter (Give your answer in volts.) V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter V

Consider the circuit in the diagram.    where R1 = R2 = R3 = 19.0 Ω and R4 = 36.0 Ω. What is the potential difference between points A and B?

Due to a weak connection, there is a break in the circuit (shown below) between points a and b. If R1 = 4.73 N, R2 = 1.99 2, and R3 = 15.7 N, and the two batteries E1 %3D and Ez have voltages of 26.0 V and 6.50 V respectively, find the potential difference Vab: Be sure to include the sign of the potential difference. Vab = Vb – Va V %3D R1 ww ww R2 ww R3 b