Consider the block of three-address code Identify leaders and generate basic blocks To = a * b T1 = To + j T2 = T0 * T1 T3 = b[T2] j = T3 T4 = j + 2 T5 = c[T4] T6 = a * b * 10 i = T6 sub=i If i <= 15 GOTO (1) note: subject: compailer concepts deptt: cs/It
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Consider the block of three-address code
Identify leaders and generate basic blocks
- To = a * b
- T1 = To + j
- T2 = T0 * T1
- T3 = b[T2]
- j = T3
- T4 = j + 2
- T5 = c[T4]
- T6 = a * b * 10
- i = T6
- sub=i
- If i <= 15 GOTO (1)
note: subject: compailer concepts deptt: cs/It
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- Define segmentation.Match the followings: Group-I (a) Pointer data type (b) Activation Record (c) Repeat -Until (d) Coercion Group-II (p) Type Conversion (q) Dynamic Data Structure (r) Recursion (s) Nondeterministic loop A a - p, b - r, c - s, d - q B a - q, b - r, c - s, d - p C a - q, b - s, c - r, d - pD a - r, b - q, c - s, d – p1. address of Compute the missing addresses based on the execution of the following C code: struct S{ inti1; char c2[2]; double d3; char c4[8]; }; void foo(struct S * p1, int n) { int * p2 = &p1->i1; char * p3 = &p1->c2[4]; struct S* p4 = p1-1; char * p5 = p1->c4; } %3D p1 = 0x2a20 p2 = p3 = p4 = p5 =
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