Consider the bar in figure 2, it has cross sectional area A = 1.10-4m², modulus of elasticity E = 200GPa, and length 1.5 m. The bar is fixed to a wall on its left hand side, and has a constant loading of 1(x) = -10 kN/m applied along its length. x=0.0 I(x) = -10 kN/m 1.5 m ə d.x Figure 2: diagram of bar subject to applied force along its length a) The displacement of the bar u(x) is governed by the equation -AE Qu(x) dx X x=1.5 +1(x) = 0 x = [0, 1.5], state the two boundary conditions for this bar problem, and give a short reasoning for your answer (maximum 2 sentences for each boundary condition)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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Consider the bar in figure 2, it has cross sectional area A = 1.10-4m², modulus of elasticity
E = 200GPa, and length 1.5 m. The bar is fixed to a wall on its left hand side, and has a constant
loading of 1(x) = −10 kN/m applied along its length.
x=0.0
|(x) = -10 kN/m
1.5 m
→ X
x=1.5
Figure 2: diagram of bar subject to applied force along its length
a) The displacement of the bar u(x) is governed by the equation
Ə du(x)
dx
AE +1(x) = 0 x = [0, 1.5],
dx
state the two boundary conditions for this bar problem, and give a short reasoning for your
answer (maximum 2 sentences for each boundary condition).
Transcribed Image Text:Consider the bar in figure 2, it has cross sectional area A = 1.10-4m², modulus of elasticity E = 200GPa, and length 1.5 m. The bar is fixed to a wall on its left hand side, and has a constant loading of 1(x) = −10 kN/m applied along its length. x=0.0 |(x) = -10 kN/m 1.5 m → X x=1.5 Figure 2: diagram of bar subject to applied force along its length a) The displacement of the bar u(x) is governed by the equation Ə du(x) dx AE +1(x) = 0 x = [0, 1.5], dx state the two boundary conditions for this bar problem, and give a short reasoning for your answer (maximum 2 sentences for each boundary condition).
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