Consider the area under one arch of the curve y(t) = 8sin(bt) for t≥0 where b is a positive constant. (a) Set up the definite integral needed to find the area. (b) Make an appropriate substitution. W = dw = dt (c) Write the definite integral in terms of w. (d) Evaluate the integral in part (c). dw

LD in evaluate the intearal (Use Ć Jor the constant -6t te dt

Use the Fundamental Theorem of Calculus to find the "area under curve" of y = - x² + 10x between x = 3 and x = 6. In your calculations, if you need to round, do not do so until the very end of the problem. Answer:

Use the Fundamental Theorem of Calculus to find the "area under curve" of y = -x² + 8x between x = 1 and x = 3. In your calculations, if you need to round, do not do so until the very end of the problem. Answer: