Consider standing waves in a pipe of length L = 3.5 m containing a column of air. The speed of sound in the columns is v. = 334 m/s. Each of the standing wave images provided may represent a case for which one or both ends are open. ▷ A 20% Part (a) Select the image from the options provided showing the gas pressure for the third harmonic of a pipe with two open ends. Grade Summary Deductions Potential 0% 100% Submissions о Attempts remaining: 100 (0% per attempt) detailed view O O Submit Hint Feedback I give up! Hints: 0 for a 0% deduction. Hints remaining: 0 Feedback: A 20% Part (b) Calculate the wavelength 3 in m for the third harmonic in the pipe with two open ends. Ө

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### Standing Waves in a Pipe with Air Column

Consider standing waves in a pipe of length \( L = 3.5 \, \text{m} \) containing a column of air. The speed of sound in the columns is \( v_s = 334 \, \text{m/s} \). Each of the standing wave images below may represent a scenario in which one or both ends of the pipe are open.

#### 20% Part (a)
**Question:**
Select the image from the options provided showing the gas pressure for the third harmonic of a pipe with two open ends.

**Options:** 
(Images are provided showing various pressure distributions in a pipe, with differing densities of dots to indicate pressure levels).

- Select the correct image by clicking the corresponding radio button.

- **Grade Summary:**
  - Deductions: 0%
  - Potential: 100%
  - Submissions: Attempts remaining: 100 (0% per attempt)

**Explanation of Diagrams:**
The correct image will show a standing wave pattern characteristic of the third harmonic in a pipe open at both ends. Typically, for an open-open pipe, each end is an antinode, and the third harmonic would have three nodes and four antinodes.

![Diagram Legend]
- Higher concentration of dots: Higher gas pressure
- Lower concentration of dots: Lower gas pressure

(Select the image that correctly represents these criteria.)

#### 20% Part (b)
**Question:**
Calculate the wavelength \( \lambda_3 \) in meters for the third harmonic in the pipe with two open ends.

**Hints:**
There are 0 hints remaining for a 0% deduction.

**Feedback:**
[Field to display feedback after submission]

---

#### Solution to Part (b):

1. The formula for the wavelength of the nth harmonic in an open pipe is:
\[ \lambda_n = \frac{2L}{n} \]

2. For the third harmonic (\( n = 3 \)):
\[ \lambda_3 = \frac{2 \times 3.5 \, \text{m}}{3} = \frac{7 \, \text{m}}{3} \approx 2.33 \, \text{m} \]

Submit your answers and review the feedback provided.
Transcribed Image Text:### Standing Waves in a Pipe with Air Column Consider standing waves in a pipe of length \( L = 3.5 \, \text{m} \) containing a column of air. The speed of sound in the columns is \( v_s = 334 \, \text{m/s} \). Each of the standing wave images below may represent a scenario in which one or both ends of the pipe are open. #### 20% Part (a) **Question:** Select the image from the options provided showing the gas pressure for the third harmonic of a pipe with two open ends. **Options:** (Images are provided showing various pressure distributions in a pipe, with differing densities of dots to indicate pressure levels). - Select the correct image by clicking the corresponding radio button. - **Grade Summary:** - Deductions: 0% - Potential: 100% - Submissions: Attempts remaining: 100 (0% per attempt) **Explanation of Diagrams:** The correct image will show a standing wave pattern characteristic of the third harmonic in a pipe open at both ends. Typically, for an open-open pipe, each end is an antinode, and the third harmonic would have three nodes and four antinodes. ![Diagram Legend] - Higher concentration of dots: Higher gas pressure - Lower concentration of dots: Lower gas pressure (Select the image that correctly represents these criteria.) #### 20% Part (b) **Question:** Calculate the wavelength \( \lambda_3 \) in meters for the third harmonic in the pipe with two open ends. **Hints:** There are 0 hints remaining for a 0% deduction. **Feedback:** [Field to display feedback after submission] --- #### Solution to Part (b): 1. The formula for the wavelength of the nth harmonic in an open pipe is: \[ \lambda_n = \frac{2L}{n} \] 2. For the third harmonic (\( n = 3 \)): \[ \lambda_3 = \frac{2 \times 3.5 \, \text{m}}{3} = \frac{7 \, \text{m}}{3} \approx 2.33 \, \text{m} \] Submit your answers and review the feedback provided.
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