Consider f(x) = arctan(x²). Find the absolute maximum and minimum of f(x) on the interval [—7, 1]. Intermediate work f'(x) = (4x^3)/(1+x^8) Critical points of in [-7, 1]. x = 0 Candidates for absolute maximum and absolute minimum. (x,y) = Conclusion The absolute minimum value is 0 The absolute maximum value is when x = when x =

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A: If you like the solution then please give it a thumbs up.... The Answer is:           Result :…

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