Consider following circuit with R1 = 62 Ω, R2 = 11 Ω, R3 = 62 / 10 Ω, R4 = 11/10 Ω and and ξ=11 V e. Calculate currents i1 , i2 and i3 ? f. Calculate the potential difference of R2 ? g. Calculate the potential difference of R3 ? h. Calculate the heat dissipation of R2 resistor i. Cross sections through two long conductors of the same length and material, with square cross sections of edge lengths are shown below. Conductor Y fits snugly within conductor X, Rank the resistance of X and Y?
Consider following circuit with R1 = 62 Ω, R2 = 11 Ω, R3 = 62 / 10 Ω, R4 = 11/10 Ω and and ξ=11 V e. Calculate currents i1 , i2 and i3 ? f. Calculate the potential difference of R2 ? g. Calculate the potential difference of R3 ? h. Calculate the heat dissipation of R2 resistor i. Cross sections through two long conductors of the same length and material, with square cross sections of edge lengths are shown below. Conductor Y fits snugly within conductor X, Rank the resistance of X and Y?
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Consider following circuit with R1 = 62 Ω, R2 = 11 Ω, R3 = 62 / 10 Ω, R4 = 11/10 Ω and and ξ=11 V
e. Calculate currents i1 , i2 and i3 ?
f. Calculate the potential difference of R2 ?
g. Calculate the potential difference of R3 ?
h. Calculate the heat dissipation of R2 resistor
i. Cross sections through two long conductors of the same length and material, with square cross
sections of edge lengths are shown below. Conductor Y fits snugly within conductor X, Rank the
resistance of X and Y?
Transcribed Image Text:The image consists of a diagram featuring two squares labeled as "X" and "Y."
- **Square X**:
- Square X is larger with a dimension of \(2L\) on each side.
- Inside Square X is another smaller square.
- **Square Y**:
- Square Y is smaller with a dimension of \(L\) on each side.
- **Distance**:
- The distance between Square X and Square Y is shown as \(L\).
This diagram is useful for visualizing problems involving geometric shapes, areas, or spatial relationships where proportional dimensions and distances are key components.
Transcribed Image Text:The image depicts an electrical circuit diagram containing four resistors and a voltage source. The circuit is arranged in a combination of series and parallel connections. Here’s a detailed breakdown of the components and their arrangements:
1. **Voltage Source**:
- Positioned on the left side between points \(a\) and \(b\).
- Provides a positive terminal at the top and a negative terminal at the bottom.
2. **Resistor \(R_1\)**:
- Located between points \(a\) and \(b\).
- The current flowing through \(R_1\) is labeled as \(i_1\), moving from \(a\) to \(b\).
3. **Resistor \(R_2\)**:
- Positioned vertically between points \(b\) and \(c\).
- The current flowing through \(R_2\) is labeled \(i_2\), moving from \(b\) to \(c\).
4. **Resistor \(R_3\)**:
- Positioned horizontally, parallel to \(R_1\), between points \(b\) and \(c\).
- The current flowing through \(R_3\) is labeled \(i_3\), moving from \(b\) to \(c\).
5. **Resistor \(R_4\)**:
- Positioned horizontally between points \(a\) and \(c\).
- Referred to without specified current direction but connects in series with the voltage source.
**Circuit Topology**:
- The circuit forms a basic loop with both series and parallel elements.
- \(R_1\) and \(R_4\) are in series with the voltage source.
- \(R_2\) and \(R_3\) form a parallel branch between points \(b\) and \(c\).
**Currents**:
- \(i_1\) flows through \(R_1\), entering node \(b\).
- At node \(b\), the current splits into \(i_2\) (through \(R_2\)) and \(i_3\) (through \(R_3\)).
- The circuit design illustrates the basic principles of current distribution in series-parallel networks.
This type of diagram is fundamental in analyzing complex electrical circuits to determine total resistance, current distribution, and voltage drops across components.
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