
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Question

Transcribed Image Text:Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a
resistor with a resistance of R ohms (1) driven by a voltage of E(t) volts (V). Given
the voltage drop across the resistor is ER RI, and across the inductor is
EL = L(dI/dt), Kirchhoff's Law gives
I(t) =
=
ER(t)
EL(t)
Now suppose an RL circuit with a 902 resistor and a 0.02H inductor is driven by a
constant voltage of 105V. If the initial resistor current is I(0) 0A, find the current I
and the voltages across the inductor EL and the resistorER in terms of time t.
=
=
=
dI
L + RI
dt
= E(t)
=
A
V
V
=
Expert Solution

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Step 1: Analysis and Introduction
Given Information:
To find:
The value of .
Concept used:
The linear differential equation is of the form .
The solution to such linear differential equation is .
Integration Formula:
Here, are constants and
is the constant of integration.
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