Consider an hydrogen-like atom with a very light particle of mass m rotating around a heavy particle of mass M which is much greater than m. The charge of the heavy particle is -e and the charge of the lighter particle is +3e. The light particle executes uniform circular motion about its center of rotation which is where the heavy particle is located. Assume that the centripetal acceleration of the lighter particle is due essentially only to the Coulomb force of attraction between the two particles. Given that the orbital angular momentum of the light particle around its center of rotation is L = mur = ħ, where v is the lighter particle's speed and r is its distance from the center of rotation, determine the speed of the lighter particle relative to the heavy particle. HINT: you might want to make use of the relation ² = 137. ke² he Recall that: ħ = 1.06 x 10-34 J-s; k=1=9x 109 Nm²/C² and e = 1.6 x 10-19 C. 4reo

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Consider an hydrogen-like atom with a very light particle of mass m rotating around a heavy particle of mass M which is much greater than m. The charge of the heavy particle is
-e and the charge of the lighter particle is +3e. The light particle executes uniform circular motion about its center of rotation which is where the heavy particle is located. Assume
that the centripetal acceleration of the lighter particle is due essentially only to the Coulomb force of attraction between the two particles.
Given that the orbital angular momentum of the light particle around its center of rotation is L = mvr =ħ, where v is the lighter particle's speed and r is its distance from the
center of rotation, determine the speed of the lighter particle relative to the heavy particle.
ke²
HINT: you might want to make use of the relation hc
1
Recall that: ħ = 1.06 x 10-34 J-s; k=
4π€0
137.
= 9 x 10⁹ Nm²/C² and e = 1.6 × 10-19 C.
Transcribed Image Text:Consider an hydrogen-like atom with a very light particle of mass m rotating around a heavy particle of mass M which is much greater than m. The charge of the heavy particle is -e and the charge of the lighter particle is +3e. The light particle executes uniform circular motion about its center of rotation which is where the heavy particle is located. Assume that the centripetal acceleration of the lighter particle is due essentially only to the Coulomb force of attraction between the two particles. Given that the orbital angular momentum of the light particle around its center of rotation is L = mvr =ħ, where v is the lighter particle's speed and r is its distance from the center of rotation, determine the speed of the lighter particle relative to the heavy particle. ke² HINT: you might want to make use of the relation hc 1 Recall that: ħ = 1.06 x 10-34 J-s; k= 4π€0 137. = 9 x 10⁹ Nm²/C² and e = 1.6 × 10-19 C.
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