Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/ (N x m^2)). The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate. Then, the potential difference between the plates is _V. Express answer in exponential format with 3 significant figures. Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is m². Use normal format and 3 SF. Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the distance between the plates is changed to 1.00 mm, then the magnitude of the electric field between the plates is N/C. Use exponential format and 3 SF.
Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/ (N x m^2)). The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate. Then, the potential difference between the plates is _V. Express answer in exponential format with 3 significant figures. Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is m². Use normal format and 3 SF. Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the distance between the plates is changed to 1.00 mm, then the magnitude of the electric field between the plates is N/C. Use exponential format and 3 SF.
Chapter7: Electric Potential
Section: Chapter Questions
Problem 99AP: Two parallel conducting plates, each of cross-sectional area 400 cm2, are 2.0 cm apart and...
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