Consider a system with Lagrangian L(q,4) = m²q* + amv (q)+ BV(q)² %3D where a and ß are constants to be determined. Does L give identical physics to the usual Lagrangian L= mq? – V(q) for a particle in a potential, for any potential V (q)? Why?
Consider a system with Lagrangian L(q,4) = m²q* + amv (q)+ BV(q)² %3D where a and ß are constants to be determined. Does L give identical physics to the usual Lagrangian L= mq? – V(q) for a particle in a potential, for any potential V (q)? Why?
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Transcribed Image Text:Consider a system with Lagrangian
L(q,4) = m²q* + amv (q) + BV(q)²
where a and ß are constants to be determined.
Does L give identical physics to the usual Lagrangian L= mq? – V(q) for a particle
in a potential, for any potential V (q)? Why?
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