Consider a steel (Young's modulus E = 200 GP a) column hinged on both sides. Its height is 1.0 m and cross-section is 10mm x 20mm. The lowest Euler critical buckling load (in N) is
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- A fixed-end column with circular cross section is acted on by compressive axial load P. The IS-ft-long-column has an outer diameter of 5 in., a thickness of 0.5 in., and is made of aluminum with a modulus of elasticity of 10,000 ksi. Find the buckling load of the column.An aluminum pipe column (E = 10,400 ksi) with a length L = 10.0 ft has inside and outside diameters d1= 5.0 in. and d2= 6.0 in., respectively (sec figure). The column is supported only at the ends and may buckle in any direction. Calculate the critical load Pcrfor the following end conditions: (a) pinned-pinned, (b) fixed-free, (c) fixed-pinned, and (d) fixed-fixed.A steel column ( E = 30 X 103 ksi) that is fixed at the base and free at the top is constructed of a W8 x 35 wide-flange member (sec figure). The column is 9.0 ft long. The force P acting at the top of the column has an eccentricity e = 1.25 in. If P = 40 kips, what is the maximum compressive stress in the column? If the yield stress is 36 ksi and the required factor of safety with respect to yielding is 2.1, what is the allowable load Pallow?
- Consider a steel (Young's modulus of E=200 GPa) column hinged on both sides. Its height is 1.0 m and cross-section is 10 mm x 20 mm. Find the lowest Euler critical buckling load (in N)?3. A hollow cylindrical cast iron column 200 mm external diameter and 25 mm thick is 6 metres in length. If both ends of the column are hinged and E= 8 x 10 N/mm². Find the Euler's critical load, and the safe load taking FOS as 3. Also find Rankine's critical load taking constant values as fc = 550 N/mm² and a = 1/1600. Also find the length of the column for which the critical loads by Euler's and Rankine's formula be equal.The steel (E = 200GPa ) column hinged on both sides. the height of the column is 1 m and cross-section is 10mm× 20mm . Calculate the lowest Euler critical buckling load?
- A steel (E = 200 GPa) column of length L = 3.2 m is anchored to a concrete foundation and supports a compressive axial load P. The cross-section has dimensions a = 185 mm and b = 213 mm. P -b Please address the following: (a) Determine the column's critical buckling load. (b) Taking the compressive stress of as 240 MPa, is the column more likely to buckle or yield? You must provide a numeric justification for your answer. (c) Considering a factor of safety F.S.-2.5, what is the maximum allowable load P? cross sectionFind the critical buckling load of the 7 m long, cross-section column made of A-36 steel with hinged joints at both ends (Figure 3). E=200 GPaDerive the Euler Buckling formula for column having fixed support at both ends. (eXPLAIN IN DETAIL IN HAND WRITTEN )
- A real rectangular steel bar supports a concentric load of 58.5kN. Both ends are fixed. If the modulus of elasticity is 210 GPa, what is the maximum length the rod can be without experiencing buckling failure? Assume the effective length factor, K, is 0.65.Rigid bar ACB is supported by an elastic circular strut DC having an outer diameter of 16 in. and inner diameter of 15.3 in. The strut is made of steel with a modulus elasticity of E = 29,000 ksi. Point load P = 4.3 kips is applied at B. 4 ft -5 ft B A 3 ft P Calculate the change in length (in inches) of the circular strut DC. (Use the deformation sign convention.) in. What is the vertical displacement (in inches) of the rigid bar at point B? (Use the statics sign convention.) in.An aluminum tube of length 0.01R (m) is used as column (fixed at both ends) carrying an axial load of 1.333R (N). If the outer diameter of the tube is 0.06R (mm),compute the inner diameter that would provide a factor of safety of 2 against buckling. Use E = 70 GPa for aluminum. Note R=993