Consider a single-degree-of-freedom system with the following equation of motion. mä+ci+kx = 0 In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 5 N/m. Successive peak displacements are ₁ = 2 mm and 2 = 1 mm. If the period of oscillation of the system is Ta = 1 s, determine the mass of the system. ooooo 112.6158 kg 15.6411 kg 0.1251 kg 3.3785 kg 56.0576 kg X1 A Ta X2

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Consider a single-degree-of-freedom system with the following equation of motion.
In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 5 N/m. Successive peak
displacements are *₁ 2 mm and 2 = 1 mm. If the period of oscillation of the system is Ta = 1 s, determine the mass of the system.
=
0 0 0 0 0
112.6158 kg
15.6411 kg
0.1251 kg
3.3785 kg
56.0576 kg
mx + cx + kx = 0
X
X1
x2
A
Td
t
Transcribed Image Text:Consider a single-degree-of-freedom system with the following equation of motion. In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 5 N/m. Successive peak displacements are *₁ 2 mm and 2 = 1 mm. If the period of oscillation of the system is Ta = 1 s, determine the mass of the system. = 0 0 0 0 0 112.6158 kg 15.6411 kg 0.1251 kg 3.3785 kg 56.0576 kg mx + cx + kx = 0 X X1 x2 A Td t
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