Consider a simple 3-component flash separation system as illustrated by the process flow sheet below. The feed could contain hexane, heptane, and octane. Here, i F stands for the inlet mass flow rate of stream i (e.g., in kg/hr) and inj is the mass fraction of species j in stream i. Using matrix calculation, compute for the mass flow rate for each outlet stream that can be denoted as x1, x2, x3. (
Consider a simple 3-component flash separation system as illustrated by the process flow sheet below. The feed could contain hexane, heptane, and octane. Here, i F stands for the inlet mass flow rate of stream i (e.g., in kg/hr) and inj is the mass fraction of species j in stream i. Using matrix calculation, compute for the mass flow rate for each outlet stream that can be denoted as x1, x2, x3. (
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
3. Consider a simple 3-component flash separation system as illustrated by the process flow
sheet below. The feed could contain hexane, heptane, and octane. Here, i
F stands for the
inlet mass flow rate of stream i (e.g., in kg/hr) and inj is the mass fraction of species j in
stream i. Using matrix calculation, compute for the mass flow rate for each outlet stream
that can be denoted as x1, x2, x3. (
![²F = X1
?n, = 0.9
n2 = 0.06
Fn; = 0.04
'F = 10
³F = x2
%3!
%3D
'n, = 0.7
'n = 0.2
'n; = 0.1
'n, = 0.1
'n2 = 0.8
'n; = 0.1
n1 = hexane
n2 = heptane
*F = x3
n3 = octane
"n, = 0.2
'n, = 0.1
4n; = 0.7
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3f4638d-befc-47ca-9779-d5b089bba4fc%2F3995c1fe-1c84-46ec-882d-482c90a7f25a%2Fot2gnl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:²F = X1
?n, = 0.9
n2 = 0.06
Fn; = 0.04
'F = 10
³F = x2
%3!
%3D
'n, = 0.7
'n = 0.2
'n; = 0.1
'n, = 0.1
'n2 = 0.8
'n; = 0.1
n1 = hexane
n2 = heptane
*F = x3
n3 = octane
"n, = 0.2
'n, = 0.1
4n; = 0.7
%3D
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