Consider a series resonance inverter with parallel-loaded delivers a load power of P of 3kW at a peak sinusoidal load voltage of Vp= 300Vand at resonance. The load resistance is R=2 ohms. The resonant frequency is fo = 15 kHz. The voltage dc input needed to deliver suchpower to the load is equal to:Select one:a. 300 Vb. 212.13 Vc. None of thesed. 86.04 V

To find the DC input voltage needed to deliver power to the load in a series resonance inverter, we…

Answered: Consider a series resonance inverter…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

ASAP It is a type of diode where it operates as a variable resistor when heated. Your answer What is the modulation index in ideal condition of AM. Your answer A form of AM where a sideband is filtered after its carrier is eliminated. Your answer What is the form of AM that used to transmit video signals of the TV system? Your answer It is a circuit in the superheterodyne receiver that adds and subtracts the frequencies of the AM signal and the local oscillator frequency. It is the extent to which the amplitude of the carrier wave is varied by modulating wave.
a) what should be the operating frequency to have a high frequency gain of 30 % lower that the mid band gain. Assume a DC gain of 100 dB & Dc cut – off frequency @ 15 KHz.?
Q2: Assume a sinusoidal signal with a frequency of 3.5 kHz and maximum amplitude of 1v. Then this signal is applied to LDM with a bit rate of 25kbps. Find the appropriate value of step size for this modulation.
Error propagation. We measure flux (f) and its uncertainty (df). Convert them into magnitude (m) and its uncertainty (dm). The signal-to-noise ratio can be written as SNR=f/df. What is the magnitude uncertainty when SNR=0.1, 1, 10, and 100?
A Phase Modulator has a phase deviation constant, Kp = 35°/V. The carrier signal is ec = 8 cos2n(800k)t, volts and the modulating signal is em = 5 sin2r(2000)t, volts. a. What is the equation of the PM signal? b. What is the maximum phase deviation? c. what is the amount of deviation in the carrier phase angle at t = 160µs?
Given a 5uF cарасitor,compute the reactance of the following: a. at 50 Hz(ans: –j636.6198 ) rad b.at 100 (ans: -j2000 N) sec c. at 60 cps (ans: -j530.5165 N)
If vsig is a triangle waveform, determine the maximum amplitude that vsig can have? Showyour calculation.
Explain how does LCR circuit work, impedance of LCR circuit in resonance, condition for resonance in LCR circuit and also discuss quality factor in LCR circuit?
(B) The signal Vin(t)-2Cos(2nfit)+2Cs (2nfat), passes through a square-law device where the output signal Voft) is given by V-(Vin)2 and fi-2 KHz and f-6KHz. Calculate the average power at the output of the square-law device.
1. If we add a Zero into a system: I. The gain slop will be increased by 20db/decade at its corner frequency. II. The gain slop will be decreased by 20db/decade at its corner frequency. III. Gain will not be affected. IV. None of the above. 2. If we add a Pole into a system: I. The phase will be increased by 90 degrees. II. The phase will decrease by 90 degrees. III. Phase will not be affected. IV. None of the above. 3. In systems, the Integrator add slop to the system gain equal to: I. 20 db/decade. II. -20 db/decade. III. 0 db/decade. IV. None of the above 4. The purpose of the Lag Compensator is: I. Improve the study state response of the close system. II. Speed up the transit response. III. All the above. IV. None of the above. 5. In the Lead Compensator: I. Z > P. II. Z < P. III. Z = P. IV. None of the above.
Q2: A modulating signal is used to modulate a carrier signal(AM modulation). Let Pr, Pc, PsB, PUSB, PLSB and u are the total power, carrier power, side band power, upper side band power, lower side band power and modulation index respectively. Prove the following: a. Pc = Pr (m2) m2 b. PsB = Pr m2 PT c. PUSB = PLSB 2+m2 2+m2

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