Consider a series RC circuit as in the figure below for which R = 3.30 MQ, C = 5.80 μF, and E S S + E R www (a) Find the time constant of the circuit. (b) Find the maximum charge on the capacitor after the switch is thrown closed. μC (c) Find the current in the resistor 10.0 s after the switch is closed. μA = 28.0 V.

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**Series RC Circuit Analysis**

Consider a series RC circuit as depicted in the diagram. The circuit consists of the following components:

- Resistor \( R = 3.30 \, \text{M}\Omega \)
- Capacitor \( C = 5.80 \, \mu\text{F} \)
- Battery with emf \( \mathcal{E} = 28.0 \, \text{V} \)

### Diagram Explanation:
- The diagram illustrates a series circuit with a switch \( S \), resistor \( R \), and capacitor \( C \). The battery is connected to supply voltage \( \mathcal{E} \).
- The switch \( S \) controls the flow of current through the circuit.

### Questions:

**(a)** Find the time constant of the circuit.

\[ \text{Time Constant} = \_\_ \text{s} \]

**(b)** Find the maximum charge on the capacitor after the switch is thrown closed.

\[ \text{Maximum Charge} = \_\_ \mu\text{C} \]

**(c)** Find the current in the resistor 10.0 s after the switch is closed.

\[ \text{Current} = \_\_ \mu\text{A} \]

To solve these problems, use the following formulas:

1. **Time Constant (\(\tau\))**: 
   \[
   \tau = R \times C
   \]

2. **Maximum Charge (\(Q_{\text{max}}\))**:
   \[
   Q_{\text{max}} = C \times \mathcal{E}
   \]

3. **Current through the Resistor (\(I(t)\))** at time \( t \):
   \[
   I(t) = \left(\frac{\mathcal{E}}{R}\right) \times e^{-t/\tau}
   \]

These equations will allow you to calculate the desired parameters for the RC circuit.
Transcribed Image Text:**Series RC Circuit Analysis** Consider a series RC circuit as depicted in the diagram. The circuit consists of the following components: - Resistor \( R = 3.30 \, \text{M}\Omega \) - Capacitor \( C = 5.80 \, \mu\text{F} \) - Battery with emf \( \mathcal{E} = 28.0 \, \text{V} \) ### Diagram Explanation: - The diagram illustrates a series circuit with a switch \( S \), resistor \( R \), and capacitor \( C \). The battery is connected to supply voltage \( \mathcal{E} \). - The switch \( S \) controls the flow of current through the circuit. ### Questions: **(a)** Find the time constant of the circuit. \[ \text{Time Constant} = \_\_ \text{s} \] **(b)** Find the maximum charge on the capacitor after the switch is thrown closed. \[ \text{Maximum Charge} = \_\_ \mu\text{C} \] **(c)** Find the current in the resistor 10.0 s after the switch is closed. \[ \text{Current} = \_\_ \mu\text{A} \] To solve these problems, use the following formulas: 1. **Time Constant (\(\tau\))**: \[ \tau = R \times C \] 2. **Maximum Charge (\(Q_{\text{max}}\))**: \[ Q_{\text{max}} = C \times \mathcal{E} \] 3. **Current through the Resistor (\(I(t)\))** at time \( t \): \[ I(t) = \left(\frac{\mathcal{E}}{R}\right) \times e^{-t/\tau} \] These equations will allow you to calculate the desired parameters for the RC circuit.
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