Prompt/Given Information:Consider a reversible isothermal expansion of vapor benzene at 450 K from 1 to 0.1 MPa. Assume that the PVT behavior of benzene obeys van der Waals equation of state. P = (RT)/(V - b) - a/V2 for benzene: a = 1884514 (cm6 * MPa)/mol2 and b = 119.47 cm3/molFor your convenience, at 450 K and 0.1 MPa the volume of vapor benzene is 37025 cm3/mol, and at 450 K and 1 MPa it is 3312.4 cm3/mol. R = 8.314 (MPa*cm3)/(mol*K).Note: 1 cm3*MPa/mol = 1 J/mol Question:Calculate the work done to the system? Calculate the work for the system if the gas was ideal?

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Answered: Consider a reversible isothermal…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Prompt/Given Information:

Consider a reversible isothermal expansion of vapor benzene at 450 K from 1 to 0.1 MPa. Assume that the PVT behavior of benzene obeys van der Waals equation of state.

P = (RT)/(V - b) - a/V²

for benzene: a = 1884514 (cm⁶ * MPa)/mol² and

b = 119.47 cm³/mol

For your convenience, at 450 K and 0.1 MPa the volume of vapor benzene is 37025 cm³/mol, and at 450 K and 1 MPa it is 3312.4 cm³/mol. R = 8.314 (MPa*cm³)/(mol*K).

Note: 1 cm³*MPa/mol = 1 J/mol

Question:

Calculate the work done to the system? Calculate the work for the system if the gas was ideal?

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