Consider a reaction A→B in a liquid phase with a second order reaction, contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Flow reactor to reach 75% conversion.
Consider a reaction A→B in a liquid phase with a second order reaction, contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Flow reactor to reach 75% conversion.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
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Please solve using the formula sheet if needed
Transcribed Image Text:Plug flow reactor
Problem 1
Consider a reaction A⇒B in a liquid phase with a second order reaction, kÃ=0.1 L/mol/hr. The feed
contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Calculate the volume of a plug
flow reactor to reach 75% conversion.
Repeat the same calculation for first order and zero order reactions.
Transcribed Image Text:n = 0
-TA = k
n = 1
-TA = KCA
n = 2
-TA = KC²
any n
=
-TA
kC
KT
CAO
Table 5.1 Performance Equations for nth-order Kinetics and A = 0
Plug Flow or Batch
CAO - CA
CAO
KT = ln
CAO
CA
kTCao =
= In
CAO
CA
(n − 1)Chokr=
8.1 Integral Table
= XA
1
1-XA
- CA
ΧΑ
1-XA
C₁ 1-n
A0/
- 1 = (1 - XA)¹-n – 1
pX₂
(20)
(3.12)
dX
(1
(3.16)
dX
(4=(x)
In
1- X
(3.29)
1- X
x₁²01²²x²-1-²-²₂2-1-²X
dX
fax-x
X
1- X
KT
CAO
dX
²14xx - ² m (1 + ex)
= ln
+ EX
KkT=
KT=
KT =
САО - СА
CAO
CAO - CA
CA
Note: for batch reactor t = t
V
for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate
V
FAo = vCAO
Mixed Flow
(Cao – CA)
-
ÁO - CA
CA
= XA
XA
1 - XA
XA
CA0(1-XA)²
ΧΑ
Cho (1 − XA)"
(14a)
(15)
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