Consider a problem of comparing the means of two population means. (If you are using a calculator to obtain answers directly, please write down the steps involved.) For sample 1: ĩi = 10.9, 51 5.4, ni = 15. For sample 2: ã2 = 12.3, 52 = 4.8, n2 = 13. %3D %3D Compute a 95% confidence interval for u1 Mz if both sample 1 and sample 2 are normally distributed; 01 = 02 nevertheless unknown. both sample 1 and sample 2 are normally distributed and we are not sure if ơ1 = 02. both sample 1 and sample 2 are normally distributed and it is given that ơ1 = 02 = 5. both sample 1 and sample 2 are not normally distributed. (Can we actually do it?)

Import the data from the Hill City Excel file into Minitab.You are trying to predict Price.Note: Mtn View=1 if there is a mountain view, 0 otherwise. The rest of the variables should be self explanatory. 1.Perform an F Test for overall significance of the model 2.Perform a T test for slope for the age variable 3. Find a 95% confidence interval for the slope of the SqFeet variable4. Create a prediction, CI, and PI for 1 new set of x values (any valid numbers you want), and interpret each.5. Run the residual plots and indicate if they show any problems with the model.

Given two dependent random samples with the following results: Population 1 43 32 39 39 44 47 37 Population 2 34 19 36 29 46 35 41 Use this data to find the 90 % confidence interval for the true difference between the population means. Let d = (Population 1 entry)-(Population 2 entry). Assume that both populations are normally distributed. Copy Data Step 1 of 4: Find the mean of the paired differences, d. Round your answer to one decimal place.

Answer question 4

QUESTION 17 Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. A researcher was interested in comparing the resting pulse rates of people who exercise regularly and the pulse rates of people who do not exercise regularly. She obtained independent simple random samples of 16 people who do not exercise regularly and 12 people who do exercise regularly. The resting pulse rates (in beats per minute) were recorded and the summary statistics are as follows. Do not exercise regularly Exercise regularly x1 = 723 beats/min x2 = 68.1 beats/min %3D s1 = 10.9 beats/min s2 = 8.2 beats/min ni = 16 n2 = 12 Construct a 95% confidence interval for mu1 - mu2, the difference between the mean pulse rate of people who do not exercise regularly and the mean pulse rate of people who…

QUESTION 9 Nabisco claims that Chip Ahoy Cookies have an x ̅=28.67 chocolate chips per cookie with a SD=2.67.  You randomly select 15 cookies from a new bag and carefully remove all the chocolate chips from each of the 36 cookies.  You find the mean of the chocolate chips for the 15 cookies is 24.27 chocolate chips per cookie.  Calculate the 99% confidence interval LOWER bound for the chocolate chips in your experiment.  (round to the nearest hundredth).