Consider a person sitting nude on a beach in Florida. On a sunny day, visible radiation energy from the sun is absorbed by the person at a rate of 30 kcal/h or 34.9 W. The air temperature is a warm 30 °C and the individual's skin temperature is 32 °C. The effective body surface exposed to the sun is 0.9 m². (Assume this same area for sun absorption, radiative transfer, and convective loss. Is this a good assumption?) a. Find the net energy gain or loss from thermal radiation each hour. (Assume thermal radiative gain and loss according to the equation 6.51 in Herman and an emissivity of 1.) Anseera 21kcal/hr or 24 -(). Eguadion (6.51) - (40Tin)Eskin Askin (Tskin – Troom) dt = (4 x 5.67 × 10-8 w/m²–Kª x (307 K)')eskin Aşkin (Tskin – Troom). (6.52) b. If there is a 4 m/s breeze, find the energy lost by convection each hour. (Use Eq. 6.61 with eq. 6.63.) Àns = 48 kcal/hr or 24W 1 (dQ Equation = h.(Tskin – Tair), (6.61) - - A dt he 10.45 – w + 10w" ,0.5 (6.63) c. If the individual's metabolic rate is 80 kcal/h (93.0 W) and breathing accounts for a loss of 10 kcal/h (11.6 W), how much additional heat must be lost by evaporation to keep the body core temperature constant? Ans = 43 kal/h or sow
Consider a person sitting nude on a beach in Florida. On a sunny day, visible radiation energy from the sun is absorbed by the person at a rate of 30 kcal/h or 34.9 W. The air temperature is a warm 30 °C and the individual's skin temperature is 32 °C. The effective body surface exposed to the sun is 0.9 m². (Assume this same area for sun absorption, radiative transfer, and convective loss. Is this a good assumption?) a. Find the net energy gain or loss from thermal radiation each hour. (Assume thermal radiative gain and loss according to the equation 6.51 in Herman and an emissivity of 1.) Anseera 21kcal/hr or 24 -(). Eguadion (6.51) - (40Tin)Eskin Askin (Tskin – Troom) dt = (4 x 5.67 × 10-8 w/m²–Kª x (307 K)')eskin Aşkin (Tskin – Troom). (6.52) b. If there is a 4 m/s breeze, find the energy lost by convection each hour. (Use Eq. 6.61 with eq. 6.63.) Àns = 48 kcal/hr or 24W 1 (dQ Equation = h.(Tskin – Tair), (6.61) - - A dt he 10.45 – w + 10w" ,0.5 (6.63) c. If the individual's metabolic rate is 80 kcal/h (93.0 W) and breathing accounts for a loss of 10 kcal/h (11.6 W), how much additional heat must be lost by evaporation to keep the body core temperature constant? Ans = 43 kal/h or sow
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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