Consider a memory of capacity 4MB. How many address lines do you think are needed to address all the locations of the given memory? O a. 4,194,604 O b. 4,194,504 O c. 4,193,304 O d. 4,194,304

Q: We already have RAM (Random Access Memory), a volatile kind of memory, so what's the point of using…

A: The answer is given in the below step

Q: For a 512k x 32 memory system, how wide does the incoming address bus needed to be in order to…

A: Given, Size of memory system = 512k x 32 For a p x q memory system, Size of address bus = log 2 p…

Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

A: Solution:: a)  Preconditions:   One clock cycle = 60 ns   Given that,   Cache access takes two clock…

Q: Suppose I wished to store 0xDEADFEED in memory, through RISC-V. Show in the table how it is stored…

A: Address a0 a0 + 1 a0 + 2 a0 + 3Byte ED FE AD DE

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A: a) Amount of memory = 2M = 2 x 220wordsThe RAM chips are 8 bits wide and contain 256K of memory. The…

Q: A byte-addressable computer uses 32-bit address to access main memory. Suppose the data cache…

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Q: Use the following figure to answer: What is the active memory bank when the following addresses are…

A: In computer architecture, the term "active memory bank" typically refers to a specific module or…

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Q: 12-5. A computer employs RAM chips of 256 × 8 and ROM chips of 1024 × 8. The computer system needs…

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Q: For a 512k x 32 memory system, how wide does the incoming address bus needed to be in order to…

A: Here is the explanation about the width of the address bus:

Q: Acomputer employs RAM chips of 256 x 8 and ROM chips of 1024 x 8. The computer system needs 2K bytes…

A: Step 1: Step 2: Step 3: Step 4:

Q: In a semiconductor ROM memory organized using 2-Dimensional addressing, the number of NMOS NOR gates…

A: Option c is correct Correct answer : c. 2^( The number of row address bits).

Q: If the size of each 4-bit memory component is 4 xn cells where n = 1G (i.e., 4 xn uniquely…

A: The answer is

Q: By assuming that X = 3, and  33 is a two digit number, consider memory storage of a 64-bit word…

A: step by step solution is presented:-

Q: Suppose that a 4M × 32 main memory is built using 128K × 8 RAM chips and memory is  word addressable…

A: a. How many RAM chips are needed? 128    (4M/128K*32/8 = 128)   b. How many chips would be involved…

Q: Answer the question below based on given portion of the memory unit with a word size of 8 bits, and…

A: Provided below is the detailed step by step explanation for finding the missing fields in the memory…

Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

A:

Q: 1 The memory units that follow are specified by the number of words times the number of bits per…

A: Below is the answer to above question. I hope this will be helpful for you...

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A: considering byte addressible memory, the starting addresses are given and size in bytes are given.…