Consider a loop of wire in a magnetic field below as well as a simple 2-part split ring commutator. Possible currents measured from an ammeter in the loop are also given. ▾ Part A When using the split ring commutator a in order to produce an electric generator. The graph of the output electric current measured by the ammeter will resemble O mechanical force must be applied to the wire loop. Graph A O mechanical force must be applied to the wire loop. Graph B DC current must run through the brushes of the commutator, Graph A O DC current must run through the brushes of the commutator, Graph B Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining Graph A Time (micro-seconds) Split Ring Commutator EMMAAA www. 1000 1000 1500 -3 Graph B Time (micro-seconds) 2000

A square, single-turn wire loop, 5 1.00 cm on a side is placed inside a solenoid that has a cir-cular cross section of radius r 5 3.00 cm, as shown in theend view of Figure P20.18. Thesolenoid is 20.0 cm long andwound with 100 turns of wire. (a) If the current in the sole-noid is 3.00 A, what is the flux through the square loop? (b) If the current in the sole-noid is reduced to zero in 3.00 s, what is the magnitude of the average induced emf in the square loop?

7. Consider two semi-infinite wires connected with a 4 circular bend and current i flowing as shown. Using an appropriate combination of the Biot-Savart Law dB = Hoi dĩ x ê Ampere's Law 4n r² PB• ds = H, ime > superposition, and symmetry to calculate B at point P as indicated. Note: You must correctly support each step and explain exactly what assumptions you are making. R

The figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. S R Rorso + The capacitor C charge through the resistor R (when the switch S is toggled to left) and discharge current through the patient's torso which is of resistance (when the switch S is toggled to right). This phenomenon allows the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.0 µF; ɛ = 1240 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 800 V in 2.1 s. (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1200 Q, calculate the voltage (in V) across the capacitor after 4.0 ms.