Consider a ladder sliding down a wall as in the figure. The variable a is the length of the ladder. The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom. Suppose that the length of the ladder is 5.5 meters and the top is sliding down the wall at a rate of 0.7 m/s. h a Calculate dx when h = 2.4. dt (Use decimal notation. Give your answer to three decimal places.) dx m/s dt Ih=2.4

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
Question
**Problem: Ladder Sliding Down a Wall**

Consider a ladder sliding down a wall as shown in the figure.

The variable \( a \) is the length of the ladder. The variable \( h \) is the height of the ladder’s top at time \( t \), and \( x \) is the distance from the wall to the ladder’s bottom.

Suppose that the length of the ladder is 5.5 meters and the top is sliding down the wall at a rate of 0.7 m/s.

Calculate \( \frac{dx}{dt} \) when \( h = 2.4 \).

(Use decimal notation. Give your answer to three decimal places.)

\[ \frac{dx}{dt} \bigg|_{h=2.4} \approx \_\_\_\_\_\_\_\_ \, \text{m/s} \]

---

**Explanation of the Diagram:**

The diagram illustrates a right triangle formed by the ladder (labeled \(a\)), the wall (height labeled \( h \)), and the ground (distance from the wall labeled \( x \)). The ladder is represented as the hypotenuse of the right triangle, while \( h \) and \( x \) are the legs of the triangle. 

The hypotenuse, \( a \), has a fixed length of 5.5 meters, while \( h \) and \( x \) change over time as the ladder slides down the wall.
Transcribed Image Text:**Problem: Ladder Sliding Down a Wall** Consider a ladder sliding down a wall as shown in the figure. The variable \( a \) is the length of the ladder. The variable \( h \) is the height of the ladder’s top at time \( t \), and \( x \) is the distance from the wall to the ladder’s bottom. Suppose that the length of the ladder is 5.5 meters and the top is sliding down the wall at a rate of 0.7 m/s. Calculate \( \frac{dx}{dt} \) when \( h = 2.4 \). (Use decimal notation. Give your answer to three decimal places.) \[ \frac{dx}{dt} \bigg|_{h=2.4} \approx \_\_\_\_\_\_\_\_ \, \text{m/s} \] --- **Explanation of the Diagram:** The diagram illustrates a right triangle formed by the ladder (labeled \(a\)), the wall (height labeled \( h \)), and the ground (distance from the wall labeled \( x \)). The ladder is represented as the hypotenuse of the right triangle, while \( h \) and \( x \) are the legs of the triangle. The hypotenuse, \( a \), has a fixed length of 5.5 meters, while \( h \) and \( x \) change over time as the ladder slides down the wall.
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