Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
expand_more
expand_more
format_list_bulleted
Related questions
Concept explainers
Topic Video
Question
thumb_up100%
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6167 patients treated with this drug, 159 developed the adverse reaction of nausea. Use a 0.01 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction?
- Identify the test statistic for this hypothesis test
- Identify the P value
- Identify the conclusion for this hypothesis test.
a) Reject H0. There is sufficient evidence to warrant rejection of the claim that 3% of users develop nausea.
b) Fail to reject H0. There is not sufficient evidence to warrant rejection of the claim that 3% of users develop nausea.
c) Reject H0. There is not sufficient evidence to warrant rejection of the claim that 3%
of users develop nausea.
d) Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that 3% of users develop nausea.
4.Since the rate of nausea appears to be relatively __________, it __________ a problematic adverse reaction.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 4 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.Similar questions
- What is meant by the sample space of an experiment?arrow_forwardWhat is an experiment?arrow_forwardA nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- Earrow_forward
- Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 34 of the 41 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 88 of the 102 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. (a) Test a claim using a hypothesis test. Ho:P1 = P2 H1: Answer : A for Pi P2 ; or answer: C for p1 # P2 Identify the test statistic. z = (Round to two decimal places as needed.) Identify the P-value. p-value Conclusion: since p-value is the significance level of a = 0.01, so ( fail to reject or reject) (b) Test claim by constructing an appropriate confidence interval < P1 - P2 < (Round to three decimal places.)arrow_forwardThe Gallup Poll asked 1015 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 477 said they supported such a tax. Does the survey provide convincing evidence that less than 42% of U.S. adults favor an internet sales tax? Use the 0.05 level of significance. 1. STATE THE NULL AND ALTERNATIVE HYPOTHESIS: 2. T STATISTIC/ P VALUE 3.REJECT OR FAIL THE NULL HYPOTHESIS 4. IS THE CLAIM SUPPORTED AT THE 0.05 LEVEL OF SIGNIFICANCE?arrow_forwardAccording to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0. 1 level of significance. What is your conclusion? Fail to reject Ho Reject Ho Ноarrow_forward
- In a study of high school students at least 16 years of age, researchers obtained survey results summarized in the accompanying table. Use a 0.05 significance level to test the claim of independence between texting while driving and driving when drinking alcohol. Are those two risky behaviors independent of each other? Click the icon to view the table of survey results. Determine the null and alternative hypotheses. H₂: H₁: Determine the test statistic. x² = (Round to two decimal places as needed.) Determine the P-value of the test statistic. ▼ P-value = (Round to three decimal places as needed.) Do the results suggest that texting while driving and driving while drinking are related? C Survey Results Texted While Driving No Texting While Driving Print Drove When Drinking Alcohol? Yes No 735 151 Done 3036 4489 X O A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving…arrow_forwardA random sample of 170 donations at a certain blood bank reveals that 84 were Type A blood. Does this suggest that the actual percentage of Type A donations differs from 45%, of the population having Type A blood? A. State H0 and Ha B. Test the hypothesis using the P-Value approach at a significance level of 3%, and express your decision. C Based on the given data, determine the extreme value without rejecting the H0.arrow_forward2. (Table: TV and Aggressiveness) In a fictional study, a pretest-posttest design was used to examine the influence of a television program on children's aggressiveness. The number of aggressive responses was measured during an observation period both before and after the television program. Calculate the appropriate test statistic to hypothesis test whether or not there is a difference in the number of aggressive behaviors in children after having viewed the television program. Use a = .05 and calculate the test statistic as a two tailed test. Table: TV and Aggressiveness Participant 1 2 3 4 5 6 7 Before 6 4 12 9 10 2 14 After 9 3 11 12 14 6 12arrow_forward
- Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 38 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 101 of the 114 subjects developed rhinovirus infections. Use a0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1=p2 H1: p1>p2 B. H0: p1≤p2 H1: p1≠p2 C. H0: p1=p2 H1: p1<p2 D. H0: p1=p2 H1: p1≠p2 Your answer is correct. E. H0: p1≥p2 H1: p1≠p2 F. H0: p1≠p2 H1: p1=p2 Identify the test statistic. Identify the P-value. What is the conclusion based on the…arrow_forwardFrom the table on the image: Construct an appropriate hypothesis test to determine whether or not there is an association between experiencing phenomena such as seeing a ghost and the age group you are in. Write the appropriate null/alternative hypothesis and carry out the test. Use a significance level of α = 0.01.arrow_forwardRhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 43 of the 49 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 79 of the 96 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≤p2 H1: p1≠p2 B. H0: p1=p2 H1: p1<p2 C. H0: p1≠p2 H1: p1=p2 D. H0: p1=p2 H1: p1≠p2 E. H0: p1≥p2 H1: p1≠p2 F. H0: p1=p2 H1: p1>p2 Identify the test statistic. z=nothing (Round to two decimal places as needed.) Identify the P-value.…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning 
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning