Consider a bi-convex lens with a diameter of 5 cm and zero thickness at its edges. A point object on the optical axis produces a real image on the opposite side. Both objects and images distances are 30 cm. The lens has a refractive index of 1.42. Using the equivalence of optical paths through the center and edge of the lens, determine the thickness of the lens at its center. 30 cm 30 cm O 0.4 cm O 0.34 cm O 0.52 cm O 0.5 cm O 0.31 cm

One side of a lens is convex with radius of curvature 30 cm. The other side is concave with radius of curvature 50 cm. The index of refraction of the lens is 1.6. What is the focal length of the lens? Group of answer choices 130 cm, converging 130 cm, diverging 31 cm, converging 31 cm, diverging

On one side of a diverging lens of focal length 42.7 cm, you position an object of height 3.27 cm somewhere along the principal axis. The resultant image has a height of 1.31 cm. How far from the lens is the object located? 51.1 cm 63.9 cm O 102.2 cm O 89.5 cm

A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College Physic