Conduct the following test at the alpha equals0.01   level of significance by determining​ (a) the null and alternative​ hypotheses, (b) the test​ statistic, and​ (c) the critical value. Assume that the samples were obtained independently using simple random sampling.   Test whether p 1 not equals p 2 . Sample data are x 1 equals 28 ​, n 1 equals 254 ​, x 2 equals 38   and n 2 equals 30

Find the power of the test for each combination of effect size and total sample size below (remember, when entering sample sizes into jamovi, you are entering the sample size for one group), and round your answers to three decimal places.Assuming effect size = 0.5: i. When total n = 6, power =  ii. When total n = 30, power =  iii. When total n = 80, power = For effect size = 0.8: i. When total n = 6, power =  ii. When total n = 30, power =iii. When total n = 80, power =

The parameters of my population distribution are: µ = 20 and σ = 5. The parameters of my sample are: Mean = 24 and n = 25.   Calculate my sample's Z score on the comparison distribution.

Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below:   a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.   b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.   c. Reject the null hypothesis because the value of z is negative.   d. Reject the null hypothesis because |−1.75|>0.04.   e. Do not reject the null hypothesis because |−1.75|>0.04.