6.4 What conditions favor rock deformation by folding? By faulting?

Folding- It is the phenomena in which rock are deformed under ductile forces and resulting structure…

Answered: conditions favor rock deformation by…

Engineering

Civil Engineering

conditions favor rock deformation by folding"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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6.4 What conditions favor rock deformation by folding? By faulting?

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If the strength (failure) envelope is horizontal (parallel to the normal stress axis), what is the maximum shear stress indicated by the Mohr’s circle?
In the Figure 5, if the Young modulus is 200 Gpa, the strain percentage in the direction of the normal force is Figure 5: у P = 400 KN → X 30 mm 1000 mm 30° Area 20 mm الاختيارات 0.28% 0.38% 0.08%
For the rock element, shown: Calculate the following stresses of interest Maximum Principal Stress Minimum Principal Stress Maximum Shear Stress Normal Stress at Failure Plane A-B Shear Stress at Failure Plane A-B SHOW COMPLETE SOLUTION
A bar 0.25 m in length having square cross-sectional area is subjected to an axial compression of 60 KN. The axial strain induced is 0.0030. Young’s modulus of 95 GPa and Poisson’s ratio is 0.27. Compute the stress, lateral deformation and cross-sectional area required.
Problem 3.16. The normal stress in two mutually perpendicular directions are 600 N/mm² and 300 N/mm² both tensile. The complimentary shear stresses in these directions are of intensity 450 N/mm². Find the normal and tangential stresses on the two planes which are equally inclined to the planes carrying the normal stresses mentioned above.
Q.23. The prinicipal stresses at a point across two perpendicular planes are 75 MN/ m² (tensile) and 35 MN/m² (tensile). Find normal, tangential stresses and the resultant stresses and its obliquity on a plane at 20° with the major principal plane.
A solid circular shaft, under pure torsion, develops maximum shear stress of 10 MPa on the surface. If the shaft diameter is halved, what will be the maximum shear stress developed corresponding to the same torque?
An aluminum bar having a cross-sectional area of 160 square millimeters carries the axial loads at the positions shown in the figure. Assume that the bar is suitably braced to prevent buckling. E = 70 GPa. 35 KN 15 KN 30 KN 10 KN -> 0.8 m 1.0 m 0.6 m B FIGURE 9 Determine the deformation at segment AB Determine the deformation at segment BC. Determine the deformation at segment CD. Determine the total deformation of the bar.