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- R1 R R3 R5 In the above circuit, R1 102, R2 = 402, R3 = 302, R4 = 202, Rs = 602. The battery voltage is %3D %3D 12V. Ω 1. The equivalent resistance of the circuit is = 2. The source current is = 3. The voltage drop across R3 is = V 4.The voltage drop across R2 is = 5. The power dissipated across R1 is = W 12V=96662&cmid%3D9729 For the following circuit in the figure below, find the power ( in units of Watt) delivered to the 2R-resistor when ɛ = 15.5 V and R = 3.0 0? 2R RFind the charge q(t) on the capacitor and the current i(t) in the given LRC-series circuit. L = 5h₁ R = q(t) i(t) 10 , C = Need Help? C A Find the maximum charge on the capacitor. (Round your answer to three decimal places.) с f, E(t) = 300 V, q(0) = 0 C, i(0) = 0 A 60 Read It
- When a R = 87.7 O resistor is connected across a 11.3 V battery, a current of 113.2 mA flows. What is the internal resistance of the battery and Terminal voltage of the battery ? A (1) E(MF) Rexternal (v external Rinternal (a) internal resistance of the battery(in 2) = (b) Terminal voltage of the battery in V = BatteryR1 R, R3 R5 In the above circuit, R1 = 10N, R2 = 402, R3 = 300, R4 = 200, R5 = 602. The battery voltage is 12V. 1. The equivalent resistance of the circuit is = 2. The source current is = A 3. The voltage drop across R3 is = 4.The voltage drop across R2 is = V 5. The power dissipated across R1 is = W 12Vc. A parallel XCR circuit obeys the differential equation Q.1c below: d²m I = C dt² 1 dm Equation Q.1c т + R dt X where: I has the current unit dimension. C has the capacitance unit dimension. R has the resistance unit dimension. m has the pole strength unit dimension. X is the unknown passive electrical component. The dimension of the pole strength, [m] and (cgs-emu) are [µ²M!/2L32 T-l], [µ!L1 T²], and [µ/2M/2L+1/2], respectively. pacitance, [C], and charge, [Q] in electromagnetic units i. Find the dimension of X in electromagnetic units (cgs-emu). ii. What is the possible passive component X, based on the answer in Q.1c(i).
- R1 R, R3 R on Rs In the above circuit, R1 = 102, R2 = 402, R3 = 302, R4 = 202, Rs = 602. The battery voltage is 12V. 1. The equivalent resistance of the circuit is = Ω 2. The source current is = 3. The voltage drop across R3 is = 4.The voltage drop across R2 is = 5. The power dissipated across R1 is = W 12VAmmeter ON TEMP COM Vn RAYOVAC 10A RAYOVAC sf BK TOO KIT 2706 R1 R2 R3 R4 200K TEMP MA COM Vn Voltmeter AL ACPMY BK TOOL KIT 2706 Let R1 = 100.5 Q, R2 = 102.1Q, and R3 = 198.9 Q. The recorded ampere meter and voltage meter's readings are I = 3.69 mA and V = 1.51 V, respectively. What is the percentage difference between the Rexn and Rth? Don't enter the "%" sign, just the absolute value in front of the "%" sign. %3D %3DConsider the combined parallel-series capacitance circuit shown below. C1 C2 60 μ 30 μ C3 40 µF + 6 V
- For the following circuit R1=R2=60 ohms , R3 = 250 ohms , R4= 325 ohms , R5= 260 ohms, and Vtotal = 35V . What is the total current (It)Determine the admittance Y for the circuit given in the figure. Take R= 4 Q. Y =-j10 2 ER The admittance Yis [ |)) mS. + wwIn the circuit below R1 = 33 Ω, R2 = 64 Ω, R3 = 118 Ω, and V = 95 V. What is the magnitude of the voltage drop across the R2 resistor?